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3 years ago

7-4[3-(4y-5)] plz help me

2 answers:

7 0

Let's simplify step-by-step. 7−4(3−(4y−5))

Distribute: =7+(−4)(3)+(−4)(−4y)+(−4)(5)=7+−12+16y+−20

Combine Like Terms: =7+−12+16y+−20=(16y)+(7+−12+−20)=16y+−25

Answer: =16y−25

valentina_108 [34]3 years ago

5 0

7 - 4[3 - (4y - 5)]
= 7 - 4[3 - 4y + 5]
= 7 - 4[-4y + 3 + 5]
= 7 - 4[-4y + 8]
= 7 + 4*4y - 4*8
= 7 + 16y - 32
= 16y - 32 + 7
= 16y - 25

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tino4ka555 [31]

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3 years ago

Read 2 more answers

A kitten and a puppy found a sausage which is 14cm long and started eating it simultaneously from each end. The kitten is eating

julsineya [31]

It takes them 12 seconds to eat the whole sausage.

<h3>What is speed?</h3>

Speed is the rate of change of distance.

Analysis:

If kitten eats x cm, then puppy will eat 14 - x cm

speed = d/t

speed of kitten = 1/2

speed of puppy = 2/3

1/2 = x/t

2/3 = 14 - x / t

t = 2x--------1

2t = 3(14 - x ) -------- 2

substitute t in equation 2

2(2x) = 3(14 - x)

4x = 42 - 3x

7x = 42

x = 42/7 = 6cm

substitute value of x in equation 1

t = 2(60 = 12 seconds.

In conclusion, it takes the both animals 12 seconds to finish the sausage.

Learn more about speed: brainly.com/question/4931057

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2 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

3 years ago