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sleet_krkn [62]
3 years ago
9

If you have 2500 to invest at 6 interest compounded quarterly. For how many years will the money need to be invested for that am

ount to triple?
Mathematics
1 answer:
andreev551 [17]3 years ago
5 0
For this case we have the following equation:
 P (t) = P * (1 + r / n) ^ (n * t)
 Where,
 P: initial investment
 r: interest rate
 n: periods
 Substituting values:
 3 * 2500 = 2500 * (1 + 0.06 / 4) ^ (4 * t)
 Rewriting:
 3 = (1,015) ^ (4 * t)
 Clearing t:
 log1.015 (3) = log1.015 ((1.015) ^ (4 * t))
 4 * t = log1.015 (3)
 t = (1/4) * log1.015 (3)
 t = 18.45 years
 Answer:
 
the money will need to be invested 18.45 years for that amount to triple
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Answer:

a) slope of secant line = 3

b) slope of tangent line = 2

Step-by-step explanation:

Given:

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                           f(x) = x^2 -2*x - 3

- The slope for f(x) @ x = 2 is:

                           slope = h + 2

Find:

a) The slope of the secant line through (2, f(2)) and (3, f(3))

b) The slope of the tangent line at x = 2

Solution:

- Since we are given the slope of the line computed via secant method. All we need to do is evaluate the slope given for respective question.

- The slope of secant line between points ( 2 , f(2) ) and ( 3 , f(3) ) is:

                             slope = h + 2

Where,  h is the step size between two points. h = 3 - 2 = 1

                             slope = 1 + 2 = 3

Hence, the slope of the secant is 3.

- The slope of tangent line @ points ( 2 , f(2) ) is:

                             slope = Lim _ h-->0 (h + 2)

Where,  h step size is reduced to infinitesimal small number. Hence, h = 0

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4 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
Vlad [161]

Answer

P(A) = 0.30

P(B) = 0.77

P(A\ n\ B) = 0.22

P(A\ u\ B) = 0.85

Explanation:

Given

See attachment for proper data presentation

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

Yes = 22 and No = 8

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

P(A) = 0.30

Solving (b): P(B)

We only consider data in the Yes column.

Here:

(1) = 22    (2) = 25 and (3) = 30

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

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P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

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Here, we only consider the similar cell in the yes column and sample 1 row.

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This is represented as: n(A n B)

n(A\ n\ B) = 22

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P(A\ n\ B) = 0.22

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This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

P(A\ u\ B) = 0.85

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