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jekas [21]
3 years ago
6

So I took a test from my teachers desk and took photos of the test questions. I am indeed cheating but I just want to know the a

nswers for the test before I take it tomorrow. Here is number 13.
It is Geometry pls help.

Mathematics
1 answer:
dsp733 years ago
5 0

Answer:

THE CORRECT OPTION IS A) ΔABC \sim Δ BDC \sim Δ ADB

Step-by-step explanation:

To be the similarity of any two triangles their corresponding angles should be congruent and their sides are proportional. From the given options only first option satisfies the proportionality of triangles .

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F(x) = (4x–5)/6 <br> Find the Inverse
noname [10]

Answer:

F^-1 (x) = 3x/2+5/4

Step-by-step explanation:

First, replace f(x) with y

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y  

Replace y with f−1(x) f − 1 ( x )

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

Hope this helps!  Stay Safe!

3 0
3 years ago
Angles P and Q are supplementary angles. If m
RSB [31]

Supplimentary angles add upto 180 degrees.

Given that angle P is three times angle Q-4 then ;

Let angle P be 3(x-4) = 3x -12

Let angle Q be x

Applying the rule of supplimentary angles;

3x-12+x=1804x-12=1804x=180+124x=192

Divide both sides by 4 to get value of x in degrees

x=\frac{192}{4}=48

x= 48 degrees

Angle Q = 48 degrees

Angle P = 3x-12 = (3*48)-12 = 132 degrees

7 0
1 year ago
What is the solution to the system of equations 7x - 11y = -9
alexdok [17]

Answer:

7x-11y+9=0

Step-by-step explanation:

4 0
2 years ago
What would the markup be???
Alja [10]
Hello!

To find the markup you have to subtract the selling price from the store price so

91 - 65 = 26

So there is a $26 markup

Hope this helps!
5 0
3 years ago
Consider the statement: For all integers n, if n3 is even then n is even. a. Explicitly write out what you are supposing and wha
Fittoniya [83]

Answer:

It is proved that if n^3 is even the n is even.

Step-by-step explanation:

Given n is any integer.

To show n^3 is even then n is even.

Proving by contrapositive suppose n^3 is odd. Then we need to show n is odd.

Then, letting k is a ny integer,

n^3=2k+1\implies n=(2k+1)^{\frac{1}{3}}

Now since (2k+1) is odd therefore n is odd.

Conversly let n is odd, then,

n=2k+1\implies n^3=(2k+1)^3

since 2k+1 is odd so n^3 is odd.

This proves, if n is even then n^3 is even.

4 0
3 years ago
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