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3 years ago

Hurry Please!!!!!

Mathematics

1 answer:

Mariulka [41]3 years ago

4 0

Don’t use his link! It’s a fake website to get you a virus

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What is 8y=48 what is the answer to the problem

valkas [14]

48 divided by 8 equals 6

so y = 6

7 0

3 years ago

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I need to know if the following questions are true or false

Triss [41]

Answer:

False

Step-by-step explanation:

To find <A, we can do 5x - 80 = 3x + 20.

As we simplify, we will get 2x = 100, which is x = 50

Therefore, <A will be 50 degrees and not 45 degrees.

Also, if you need y, you can do:

3y - 7 = y + 7

2y = 14

y = 7

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3 years ago

Which statement is correct?

quester [9]

Answer:

Step-by-step explanation:

Petra

3 0

3 years ago

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Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

point S lies an AB. If AB=34 units, AS=5+2x units, and SB=x+2 units, what is the length of AS in units?

vichka [17]

Answer:

5+2x+x+2=34

7+3x=34

7-7+3x=34-7

3x=27

3x/3=27/3

x=9

5+2x=AS

5+(2*9)=AS

5+18=AS

23=AS

23 units

Step-by-step explanation:

3 0

3 years ago