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Marina86 [1]
3 years ago
13

Challenge questions 1

Mathematics
1 answer:
Maru [420]3 years ago
5 0

9)

\frac{24z^{5}y^{4}}{3z^{-2}y^{5}} = \frac{24}{3}*\frac{z^{5}}{z^{-2}}*\frac{y^{4}}{y^{5}} = \frac{8}{1} *\frac{z^{5+2}}{1}*\frac{1}{y^{5-4}} = \frac{8z^{7} }{y}

11)

(a²b)³ = a²⁽³⁾b¹⁽³⁾ = a⁶b³

12)

The exponent tells you how many places to move the decimal. The positive/negative sign tells you which direction to move the decimal (negative is left, positive is right).

8.4 x 10⁻⁵ <em>move the decimal 5 places to the left</em>   =  0.000084


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765903 rounded to the nearest thousand
Anna11 [10]
I belive it would be 765000
3 0
3 years ago
If 2.5kg of washing powder<br> costs $4 find the cost of 1kg
Agata [3.3K]
Answer: $ 1.60

1.Set up the proportion, 2.5/4 = 1/x.
2. Cross multiply. 2.5x = 4
3. Divide both sides by 2.5. x = 1.6
8 0
4 years ago
P(A)= .50 P(B)=.80 P(A and B)=.20 what is P(B/A)
Reil [10]

Answer:

Final answer is P(B|A)=0.40.

Step-by-step explanation:

Given that P(A)= .50, P(B)=.80 , and P(A and B)=.20.

Now we need to find about what is the value of P(B/A).

So apply the formula of compound probability :

P(A and B) = P(A)*P(B/A)

Plug the given values into above formula

0.20 = 0.50*P(B/A)

0.50*P(B/A) = 0.20

P(B|A)=\frac{0.20}{0.50}

P(B|A)=0.40

Hence final answer is P(B|A)=0.40.

5 0
3 years ago
Kristen spent $131 on shirts. Fancy shirts cost $28 and plain shirts cost $15. If she bought a total of 7 then how many of each
Sloan [31]
<span>1 x + 1 y = 7 .............1
Total value
15 x + 28 y = 131 .............2
Eliminate y
multiply (1)by -28
Multiply (2) by 1
-28 x -28 y = -196
15 x + 28 y = 131
Add the two equations

-13 x = -65
/ -13
x = 5
plug value of x in (1)
1 x + 1 y = 7
5 + y = 7
y = 7 -5
y = 2
y = 2
x= 5 plain shirts
y= 2 fancy shirts </span>
3 0
3 years ago
Keith had 37 peaches left at his roadside fruit stand. He went to the orchard and picked more peaches to stock up the stand. The
kodGreya [7K]

Answer:

35

Step-by-step explanation:

37 + x = 72

x = 72 - 37

x = 35

3 0
3 years ago
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