Answer:

Step-by-step explanation:
let
denote grams of
formed in
mins.
For
of
we have:
of A and
of B
Amounts of A,B remaining at any given time is expressed as:
of A and
of B
Rate at which C is formed satisfies:

Apply the initial condition,
,to the expression above

Now at
:

Substitute in X(t) to get

By Pythagoras AB^2 = 12^2 - 6^2 = 108
AB = sqrt 108 = 10.39 to nearest hundredth
The perpendicular from M to DC will be parallel and equal to AB so it = 10.39.
Also AB^2 = CB * DB
108 = 6 * DB
DB = 108/6 = 18
so DC = 18-6 = 12
MD^2 = (1/2*12)^2 + 108 = 144
so MD = 12