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Georgia [21]
3 years ago
5

Please write and solve the equation for me​

Mathematics
2 answers:
tia_tia [17]3 years ago
4 0

Answer: cross out 2/7 and leave the A

which would make it 1/2 = A

Step-by-step explanation:

sergey [27]3 years ago
3 0

Answer: ok

Step-by-step explanation:

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Norma earns $22 per hour. She donates 5% of her wages to her favorite charity. If she wants to have at least $748 left after her
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I did the math on a calculator and i got C 36.
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A news report says that 28%of high school students pack their lunch. Your high school has 600 students. How many students in you
Vesnalui [34]
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Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

5 0
2 years ago
HELP ME PLEASE!!! MATHEMATICS
sukhopar [10]
By Pythagoras  AB^2 = 12^2 - 6^2 =  108

AB = sqrt 108 = 10.39 to nearest hundredth

The perpendicular from M to DC will be parallel and equal to AB so  it = 10.39.

Also  AB^2 = CB * DB

108  =  6 * DB
DB = 108/6  = 18
so DC = 18-6 = 12

MD^2 = (1/2*12)^2 + 108  =   144

so MD = 12
5 0
3 years ago
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