Answer:
1.1 qt/s
Step-by-step explanation:
To find quarts per second, divide quarts by seconds:
(63 qt)/(56 s) = 9/8 qt/s ≈ 1.1 qt/s
5*4^2-3*4*5=80-60=20
Hope that helps you
Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
Answer:
I believe it is the second answer;
F(x)= (1/2)(2)^x
Step-by-step explanation:
1. the initial value is 0.5, so the first number will have to be 1/2, and it is increasing so the value of <em>b</em> must be above 1.
2. Through process of elimination, you can determine that the second equation matches the graph.
I hoped this helped! Please comment if you have any questions :)
Answer:
-5
Step-by-step explanation:
or, f(x) = -x^2+10x+16
or, f(7) = (-7)^2+10*-7+16 (-7*-7=49)
=49-70+16
=65-70
=-5
