Question

The space shuttle releases a space telescope into orbit

Answer 1

Answer: $68 m/s^{2}$

Step-by-step explanation:

The acceleration $a$ of the satellite can be calculated by the following equation:

$V_{f}=V_{o}+at$

Where:

$V_{f}=1700 m/s$ is the final speed of the satellite

$V_{o}=0$ is the initial speed of the satellite (it was "stationary" before the release)

$t=25 s$ is the time

Isolating $a$:

$a=\frac{V_{f}}{t}$

$a=\frac{1700 m/s}{25 s}$

Finally:

$a=68 m/s^{2}$