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2 years ago

The space shuttle releases a space telescope into orbit

Mathematics

1 answer:

sergey [27]2 years ago

4 0

Answer: $68 m/s^{2}$

Step-by-step explanation:

The acceleration $a$ of the satellite can be calculated by the following equation:

$V_{f}=V_{o}+at$

Where:

$V_{f}=1700 m/s$ is the final speed of the satellite

$V_{o}=0$ is the initial speed of the satellite (it was "stationary" before the release)

$t=25 s$ is the time

Isolating $a$ :

$a=\frac{V_{f}}{t}$

$a=\frac{1700 m/s}{25 s}$

Finally:

$a=68 m/s^{2}$

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The answer is D

Step-by-step explanation:

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Germany, Italy, and Japan formed the Tripartite Pact in part because they:

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Answer:

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2 years ago

What is the answer to 19+x/2=4?

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19+x/2=4
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2 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

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2 years ago

NEED HELP ASAP PLEASS AND THANK YOU

Ghella [55]

Answer:

Using points ( 2 , - 4) and ( 0 , 2)

Slope = 2+4/0-2 = 6/-2 = - 3

Since the lines are parallel their slope will be the same

So the slope of the line parallel to the one in the picture is - 3

That's option A.

Hope this helps.

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2 years ago

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