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oksano4ka [1.4K]
1 year ago
15

Identify the shape of the cross section of the given figure. O Square O Rectangle O Trapezium

Mathematics
1 answer:
suter [353]1 year ago
3 0

To find the answer, look at the graph and compare to the shapes shown below:

Choose the option that is most likely to the shape on the question.

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PLEASE HELP ASAP!!!<br><br> Y= [?] degrees
Elis [28]

Answer:

y = 25 degrees

Step-by-step explanation:

We start with 115° and x -

115° + x = 180°

x = 180° - 115°

x = 65°

The sum of all of the angles of a triangle will <em>always</em> be 180 degrees -

x + y + 90° = 180°

We substitute x with 65° -

65° + y + 90° = 180°

y = 180° - 65° - 90°

y = 90° - 65°

y = 25°

6 0
3 years ago
How many ways can a 7 question multiple choice test be answered? (assume that there are 5 possible responses per question?
sweet [91]
I am assuming that you can only pick one answer per question.

Let's imagine there are two questions on the test. I would:

1) Consider the first question. How many possible ways could you answer it?

2) Consider the second question. How many ways can you answer that?

If you wrote out all the possibilities, how many combinations of answers would you get across the two questions?
3 0
3 years ago
How do you turn f(x) = 3x 2– 40x + 180 into a graph?
Nuetrik [128]

Answer:

Intersept is (4.55,0)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
2(x-7)+3=2x-10<br> This question has how many solutions
ycow [4]
I believe the answer is 0=1
8 0
2 years ago
Read 2 more answers
Divide line segments
ser-zykov [4K]

tis noteworthy that the segment contains endpoints of A and C and the point B is in between A and C cutting the segment in a 1:2 ratio,

\bf \textit{internal division of a line segment using ratios} \\\\\\ A(-9,-7)\qquad C(x,y)\qquad \qquad \stackrel{\textit{ratio from A to C}}{1:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{1}{2}\implies \cfrac{A}{C}=\cfrac{1}{2}\implies 2A=1C\implies 2(-9,-7)=1(x,y)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill

\bf B=\left(\cfrac{(2\cdot -9)+(1\cdot x)}{1+2}\quad ,\quad \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}\right)~~=~~(-4,-6) \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -9)+(1\cdot x)}{1+2}=-4\implies \cfrac{-18+x}{3}=-4 \\\\\\ -18+x=-12\implies \boxed{x=6} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}=-6\implies \cfrac{-14+y}{3}=-6 \\\\\\ -14+y=-18\implies \boxed{y=-4}

6 0
3 years ago
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