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oksano4ka [1.4K]
1 year ago
15

Identify the shape of the cross section of the given figure. O Square O Rectangle O Trapezium

Mathematics
1 answer:
suter [353]1 year ago
3 0

To find the answer, look at the graph and compare to the shapes shown below:

Choose the option that is most likely to the shape on the question.

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Help please. Just need to answer 29-31 then I’m done. Thanks
Free_Kalibri [48]

Answer:

29. See table below

30. See attached graph

31. The slope is m= 0.10

The slope represent the cost for every additional call minute.

Step-by-step explanation:

The cost is $0.5  first minute and $0.10 for any additional minutes

If c is the total cost of a call that last t minutes then;

c= 0.10t + 0.5-----where t is the time the call lasted

29. Use the equation above to create the table as;

t {x}            c{y}

1                  0.6

2                 0.7

3                 0.8

4                 0.9

5                 1.0

6                 1.1

The graph of this plot is as attached , where the coordinates are

{1,0.6} , {2,0.7} ,{3,0.8} ,{4,0.9} ,{5,1.0}, {6,1.1}

The slope can be found using the formula;

m=Δy/Δx

m= 1.1 - 0.6 / 6-1

m= 0.5 / 5 = 0.10

The slope represent the cost for every additional call minute.

5 0
2 years ago
You are throwing darts at a dart board. You have a 1/ 6 chance of striking the bull's-eye each time you throw. If you throw 3 ti
Bogdan [553]

B. 1/216

bc 1/6*1/6*1/6

4 0
3 years ago
Read 2 more answers
Simplify:–4(7x – 3y – z) – (–6)(9x – z + 2)
Zielflug [23.3K]
It is a cause i had that on a test
8 0
3 years ago
Read 2 more answers
What is the measure of angle B?
Andre45 [30]

60 degrees, because it's an equilateral triangle, as you can tell because the sides are all the same length.

3 0
3 years ago
Which equation matches the graph below?
Oksana_A [137]

Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:

y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5

To try to discard one of them, let us use the vertex, which is at x = -2.

With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.

Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.

Step-by-step explanation:

6 0
3 years ago
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