Answer:
48
Step-by-step explanation:
times 4 times 3 times 4 + 48
Answer:
Option D. dilation and reflection
Step-by-step explanation:
we know that
A reflection, rotation and a translation transformations, creates a triangles that are congruent
A dilation transformation, create a triangles that are similar
therefore
the answer is the option D
First step, i would try to figure out the slope. think of it as a typical y=mx+b linear equation as you check out the graph.
it's just rise over run (rise up this many, run over that many), and your options are (-2/3) or (-3/2)
start at the y-intercept, which is just above the middle of the graph. if you go down 2 and try to go over 3, you hit the line before you can count 3 units. that means this slope is incorrect.
go back to the y-intercept. down 3, over 2--there you go. your slope here is (-3/2), which immediately gets rid of half your answer choices for having the wrong slope
the next thing you have to do is decide <em>where</em> this graph should be shaded. the shaded region shows the domain; the white region shows what's outside of your domain. this inequality is shaded "below" which means that the y values are LESS than "(-3/2)x +1"
that eliminates another one of your answer choices; choice 3 is correct. the inequality is y < (-3/2)x + 1
if the graphs of inequalities are shaded below and the line is dotted, it's less than. if the graphs of inequalities are shaded above and the line is dotted, it's greater than. general rules for ya
Step-by-step explanation:
i cant help
you have a quadratic equation that can be factored, like x2+5x+6=0.This can be factored into(x+2)(x+3)=0.
So the solutions are x=-2 and x=-3.
2.
<span><span>1. Try first to solve the equation by factoring. Be sure that your equation is in standard form (ax2+bx+c=0) before you start your factoring attempt. Don't waste a lot of time trying to factor your equation; if you can't get it factored in less than 60 seconds, move on to another method.
</span><span>2. Next, look at the side of the equation containing the variable. Is that side a perfect square? If it is, then you can solve the equation by taking the square root of both sides of the equation. Don't forget to include a ± sign in your equation once you have taken the square root.
3.</span>Next, if the coefficient of the squared term is 1 and the coefficient of the linear (middle) term is even, completing the square is a good method to use.
4.<span>Finally, the quadratic formula will work on any quadratic equation. However, if using the formula results in awkwardly large numbers under the radical sign, another method of solving may be a better choice.</span></span>
