Answer:
Step-by-step explanation:
The answer is 1/27
due to
(1/3)^3 = [(1)^3]/[3^3] =1/27
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Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
Answer:
you lost me at composite
Step-by-step explanation:
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