Answer:
1. 18 (sqrt21 - sqrt2a)
2. 3
3. x^m/n
4. (5x^4√10)/(√2x)
5. x = -2 or -6
6. x = 30
Step-by-step explanation:
Number 1
3^3sqrt21 - 6^3sqrt2a
3 * 6 * sqrt21 - sqrt2a
18 (sqrt21 - sqrt2a)
Number 2
3^1/2 * 3^1/2 =
3^1/2+1/2 =
3^1 =
3
Number 3
^nsqrtx^m =
x^m/n
Number 4
(√250x^16)/(√2x) =
(√25 * 10 * x^16)/√(2x )=
(5x^4√10)/(√2x)
Number 5
√2x + 13 - 5 = x
√2x + 13 = x + 5
square both side to take away the sqrt sign
(√2x + 13)^2 = (x + 5)^2
expand the equation on the RHS
2x + 13 = x(x+5) + 5(x+5)
2x+13 = x^2 + 10x +25
substract 13 from both sides
2x = x^s + 10x +12
subtract 2x from both sides
0 = x^2 +8x + 12
Factorize equation
x^2 + 6x +2x + 12 = 0
x(x+6) + 2(x+6) = 0
(x+2)(x+6) = 0
x = -2 or -6
Number 6
3 ^5sqrt(x+2)^3 + 3 = 27
subtract 3 from both sides
3 ^5sqrt(x+2)^3 = 27 - 3
3 ^5sqrt(x+2)^3 = 24
divide through by 3
^5sqrt(x+2)^3 = 8
square both sides by 5 to take away the 5th root sign
(x+2)^3 = (8)^5
(x+2)^3 = 32,768
take the cube root of both sides to take away the ^3
x+2 = ^3sqrt 32,768
x+2 = 32
x = 32 - 2
x = 30
The numbers from which we are to determine the smallest number that can be divided leaving a remainder of 5 are 44, 55, and 220. We have to do the prime factorization of all the numbers to determine their least common multiple (LCM).
Factorization of 44:
44 = 11 x 4 = 11 x 2 x 2
Factorization of 55:
55 = 11 x 5
Factorization of 220:
220 = 11 x 20 = 11 x 5 x 4
Since 220 has all the factors from 55 and 44 then, the least common multiple is 220. Add 5 to the LCM in order to determine the unknown.
<em>ANSWER: 225</em>
X/13 2/7
X=2/7*(13)
X=26/7 Final Answer
To simplify this use the distributive property.
4(5x)= 20x
4(8)=32
4(3p)=12p
Your simplified answer is
20x+12p+32
This is asking for x and y coordinates. for example, 1 ticket is $34, right? so on the x side, there is a 1, and on the y side theres a 34. the order pair would be (1, 34). then graph it. the equation would be y=34x. hope this helps!
