What figure has 4 sides & only one pair of parallel lines

Mathematics

1 answer:

Leto [7]3 years ago

3 0

This is a trapezoid. It is a quadrilateral and only has 1 pair of parallel sides

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Fill in each box with the correct number or variable.

Licemer1 [7]

Answer:

8 would be there.

Step-by-step explanation:

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4 0

3 years ago

Which of the following ordered pairs belongs to the graph of f(x)

Lera25 [3.4K]

Answer:

The second choice, $(-1,\, 12)$ .

Step-by-step explanation:

Note, that the expression $y = f(x)$ is an equation. A point $(x,\, y)$ is on the graph of $y = f(x)\!$ if and only if the value of $x$ and $y$ satisfy this equation; that is: in other words, the $y\!$ -coordinate of that point (the second number in the tuple) should be equal to $f(x)$ , which is equal to $(-3\, x +9)$ (evaluated where $x\!$ is equal to the first number in the tuple.

For each tuple in the choices, calculate the value of $f(x)$ where $x$ is equal to the first number of each tuple. Compare the result to the second number in that tuple. That choice corresponds to a valid point on $y = f(x)$ only if these two numbers match.

First choice: $x = 1$ , $f(x) = f(1) = -3 + 9 = 6$ . That's not the same as the second number, $-10$ . Therefore, this point isn't on the graph of $y = f(x)$ .
Second choice: $x = -1$ , $f(x) = f(-1) = (-3)\times (-1) + 9 = 3 + 9 = 12$ . That matches the second number in the tuple. Therefore, this point is on the graph of $y = f(x)$ .
Third choice: $x = 2$ , $f(x) = f(2) = (-3)\times 2 + 9 = 3$ . That's not the same as the second number, $(-3)$ . Therefore, this point isn't on the graph of $y = f(x)$ .
Fourth choice: $x = -2$ , $f(x) = f(-2) = (-3)\times (-2) + 9 = 15$ . That's not the same as the second number, $13$ . Therefore, this point isn't on the graph of $y = f(x)$ .