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nika2105 [10]
3 years ago
11

How many units of a 10% solution are needed to prepare 500 units of a 2% solution?

Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0
First find how many units of solution there is:

500* 2% = 500(.02) = 10 units

You need 10 units of solution in 'x' units of a 10% solution.

x*10% = 0.1x = 10 units   ----->  x = 10/0.1 = 100

100 units are needed
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1) When the denominator equals zero that is a critical point

=> x - 2 = 0 => x = 2.

So x = 2 is a critical point

2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)

Multiply both terms:

[2x + 5] / [ x - 2] = [x - 1] / [x - 2]

for x ≠ 2 => 2x + 5 = x - 1

=> 2x - x = - 1 - 5

=> x = - 6

Then, the two critical points are x = 2 and x = - 6.

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Hello,
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Answer:

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