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riadik2000 [5.3K]
4 years ago
13

it has rained on the 6th of january twice in the last 20 years calculate the probability that it will rain on the 6th january ne

xt year​
Mathematics
1 answer:
lorasvet [3.4K]4 years ago
6 0
There is obviously an infinite amount of probabilities in which it will rain on the 6th of January

But 50/50, because just because it happened other times doesn’t mean it’ll happen again

Hope this helped ♥︎
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2/3 employees of a company drive to work, 1/3 travel by bus and the rest walk . find the number of who walk.​
olasank [31]
Zero
2/3 drive plus 1/3 bus = 3/3 or 1 whole
Cannot be any that walk
8 0
2 years ago
What is the mean absolute deviation of the following set
Verdich [7]

Answer:

1

Step-by-step explanation:

The mean absolute deviation of a dataset is the average distance between each data point and the mean.

4 0
3 years ago
Let |x| + |y| = c where, c is s real number. Determine the number of points that would be on the graph of the equation for each
IRINA_888 [86]

Answer:

  1. 0
  2. 1
  3. an infinite number

Step-by-step explanation:

<u>Case 1</u>

The absolute value of a number will not be negative, so the function is the sum of two non-negative numbers. That sum cannot be negative, so there will be no points on the graph.

<u>Case 2</u>

The sum of two non-negative numbers can be zero if they both are zero. This graph will have exactly one point: (x, y) = (0, 0). (In the attached, it doesn't show up.)

<u>Case 3</u>

There are an infinite number of ways two non-negative numbers can sum to a positive number. There will be an infinite number of points on the graph. The line segments in the attached graph illustrate that for c = 1.

8 0
3 years ago
How many eggs did she use
MAXImum [283]
She used three eggs because 3 X 4 =12
8 0
3 years ago
Read 2 more answers
A random sample of 384 people in a mid-sized city (city one) revealed 112 individuals who worked at more than one job. A second
Svetlanka [38]

Answer:

99% confidence interval is:

(0.00278 < P1 - P2< 0.15921)

Step-by-step explanation:

For calculating a confidence intervale for the difference between the proportions of workers in the two cities, we calculate the following:

[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }

             Where  p_{1} : proportion sample of individuals who worked      

                                                     at more than one job in the city one

                           n_{1}: Number of respondents in the city one

                           p_{1} : proportion sample of individuals who worked      

                                                     at more than one job in the city two

                           n_{1}: Number of respondents in the city two

Then

α = 0.01 and α/2 = 0.005

and z_{\alpha/2} = 2.575

p_{1} = \frac{112}{384} = 0.2916

p_{2} = \frac{91}{432} = 0.2106

n_{1}= 384  and n_{2}= 432

The confidence interval is:

[(0.2916 - 0.2106) \pm 2.575 \sqrt{\frac{0.2916(1-0.2916)}{384} + \frac{0.2106(1-0.2106)}{432} }

(0.00278 < P1 - P2< 0.15921)

5 0
3 years ago
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