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Jet001 [13]
3 years ago
10

Let |x| + |y| = c where, c is s real number. Determine the number of points that would be on the graph of the equation for each

given cases:
Case 1: c < 0
Case 2: c = 0
Case 3: c > 0

Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0

Answer:

  1. 0
  2. 1
  3. an infinite number

Step-by-step explanation:

<u>Case 1</u>

The absolute value of a number will not be negative, so the function is the sum of two non-negative numbers. That sum cannot be negative, so there will be no points on the graph.

<u>Case 2</u>

The sum of two non-negative numbers can be zero if they both are zero. This graph will have exactly one point: (x, y) = (0, 0). (In the attached, it doesn't show up.)

<u>Case 3</u>

There are an infinite number of ways two non-negative numbers can sum to a positive number. There will be an infinite number of points on the graph. The line segments in the attached graph illustrate that for c = 1.

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If anyone is good at math and knows how to do this problem please answer. I will give more points
Dominik [7]

Answer:

1, 5, 13, 29, 61

Step-by-step explanation:

2^(n+1) - 3

n = 1

2^(1+1) - 3

2² - 3

4 - 3

1

n = 2

2^(2+1) - 3

2³ - 3

8 - 3

5

n = 3

2^(3+1) - 3

2³ - 3

16 - 3

13

n = 4

2^(4+1) - 3

2⁵ - 3

32 - 3

29

n = 5

2^(5+1) - 3

2⁶ - 3

64 - 3

61

4 0
3 years ago
Solve the above equation for x.
Stella [2.4K]

Answer:

x=6

Step-by-step explanation:

(1/3x+2=4)x3

x+6=12

x=12-6

x=6

8 0
2 years ago
Read 2 more answers
Suppose that the amount of algae in a pond dobles every 6 hours. If the pond initially contains 50 ponds of algae, how much alga
Vikki [24]
Well we know the algae doubles three times.
So take 50 x 2 = 100
take 100 x 2= 200
200 x 2 = 400

So the answer is A
5 0
3 years ago
What is 35.125 as a mixed number??
Sever21 [200]
The number can be separated into 35+0.125
0.125 can be rewritten as,
\frac{125}{1000}
So, the number can be rewritten;
35+\frac{125}{1000}
35\frac{125}{1000}
5 0
3 years ago
A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =
vovikov84 [41]
A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 5, 6, 7, 9}

(B ∪ C) = {1, 2, 4, 5, 6, 7, 8, 9, 10}
so
A ∩ (B ∪ C) = {1, 5, 7 , 9}
6 0
3 years ago
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