Check if there is a giggle throughout the full equation, since there isn’t, we group the equation and we get
(4ax-10bx)+(6ay-15by)
Factor out the gcf of the two groups
2x(2a-5b)+3y(2a-5b)
Not sure how to explain this step in words but so do this
(2x+3y)(2a-5b)
The solution is (2x+3y)(2a-5b)
The only of these that is a proper set of ordered pairs for this equations is A) (0,-4) (1,2) (3,14)
In order to prove this, you need to put each ordered pair into the equation and prove that it is a true statement. Below are the examples of this for A.
(0, -4)
y = 6x - 4
-4 = 6(0) - 4
-4 = 0 - 4
-4 = -4 (TRUE)
(1, 2)
y = 6x - 4
2 = 6(1) - 4
2 = 6 - 4
2 = 2 (TRUE)
(3, 14)
y = 6x - 4
14 = 6(3) - 4
14 = 18 - 4
14 = 14 (TRUE)
Therefore, each of these ordered pairs works in the equation.
Answer:

Step-by-step explanation:
we know that
Using proportion

20/3 - Take the 6 2/3, multiply the 6 and the 3 (6 x 3 = 18), then add the 2 (18 + 2 = 20). Put that number over the original 3 and you've got yourself a mixed number.