Answer:
Your answer is 3x = 15
Step-by-step explanation:
3x = 15
Since 3 is being multiplied by x, we divide both sides by 3. 3x/3 cancels out, and you're left with x.
15/3 = 5
x = 5
This is my take using algebraic methods.
The first step to solving this problem is Multiplying In(x-1).
Answer:
Volume of sphere is ![35.98cm^3](https://tex.z-dn.net/?f=35.98cm%5E3)
Step-by-step explanation:
It is given that Hal says that volume of sphere is ![36cm^3](https://tex.z-dn.net/?f=36cm%5E3)
Volume of sphere is given by ![V=\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
![\frac{4}{3}\pi r^3=36](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%3D36)
![\pi r^3=27](https://tex.z-dn.net/?f=%5Cpi%20r%5E3%3D27)
![r^3=8.594](https://tex.z-dn.net/?f=r%5E3%3D8.594)
![r=2.048cm](https://tex.z-dn.net/?f=r%3D2.048cm)
Now using 3.14 in place of ![\pi](https://tex.z-dn.net/?f=%5Cpi)
Now volume of sphere is
![V=\frac{4}{3}\times 3.14\times 2.048^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Ctimes%203.14%5Ctimes%202.048%5E3)
![V=35.98cm^3](https://tex.z-dn.net/?f=V%3D35.98cm%5E3)
Therefore volume of sphere when we use 3.14 in place of
is ![35.98cm^3](https://tex.z-dn.net/?f=35.98cm%5E3)
And the Hal likely error is he uses
directly for calculation of volume.
Answer:
a. 18 b. 119°, 118°
Step-by-step explanation:
a. Given angles are vertical, so they are equal.
6a+11 = 2a+83
6a-2a = 83-11
4a = 72
a = 72/4
a = 18
b. Substituting the value of a in the given angles,
6a+11 = 6*18+11 = 108+11 = 119°
2a+83 = 2*18+83 = 36+83 = 118°