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Dmitry [639]
3 years ago
5

What do the graphs of all arithmetic sequences have in common

Mathematics
1 answer:
jasenka [17]3 years ago
3 0
Think of how arithmetic sequences act. They start at a given number, and then they march up or down by the same distance each time. For example:

3, 7, 11, 15, 19, ...

this one marches up by 4 each time.

If this is plotted on a graph, the first point is (1,3), then (2,7), then (3,11), then (4,15) and so on. You'll notice that the slope is the same between all the points. In other words, you get a straight line! This is true for any arithmetic sequence.
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Step-by-step explanation:

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Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

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0.84=0.04(21)

So the principal square root of 0.04 is 0.2

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tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

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Step-by-step explanation:

62+34=96

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