Geometry. im giving 25 points! Please help me.

glenn needs 20 minutes to clean his room. if his little sister veronika pulls things out while he is cleaning, it takes 60 minut

mihalych1998 [28]

The answer is 50 minutes

6 0

2 years ago

Read 2 more answers

I need graph help plz

Likurg_2 [28]

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph → x = 0, 6

Maximum value of the graph → f(x) = 120

Part B

Increasing in the interval → 0 ≤ x ≤ 3

Decreasing in the interval → 3 < x ≤ 6

As the price of goods increase in the interval [0, 3], profit increases.

But in the price interval of (3, 6] profit of the company decreases.

Part C

Average rate of change of a function 'f' in the interval of x = a and x = b is given by,

Average rate of change = $\frac{f(b)-f(a)}{b-a}$

Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,

Average rate of change = $\frac{f(3)-f(1)}{3-1}$

= $\frac{120-60}{3-1}$

= 30

6 0

2 years ago

Which of the following is 38/6 converted to a mixed number

Monica [59]

6 goes into 38 6 times (6 * 6 = 36). We can bring out a whole number of 6 into our mixed number. Now, we have 2/6 left over. That can be reduced to 1/3. Your mixed number is $6\frac{1}{3}$

7 0

2 years ago

HELp ASAP!!!! Natalie works in a toy shop and earns $43 per day. She earns an extra $3 for each toy she sells. If Natalie wants

MrRa [10]

The answer is letter A !

8 0

2 years ago

Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

So

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

So

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

5 0

3 years ago