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1 year ago

Pls help !!! pleaseee.

Mathematics

1 answer:

ladessa [460]1 year ago

8 0

I guess B. That statement is grammatically incorrect.

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What is 1/7+ x = 2/3x

navik [9.2K]

1/7 + x = 2/3x
1/7 = 2/3x-x
1/7 = 2/3x - 1x
1/7 = -1/3x
-3/7 = x

6 0

3 years ago

Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB

Snowcat [4.5K]

Answer:

Step-by-step explanation:

sum of angles of parallelogram=360 degrees

adjacent angles add up to 180 degrees (supplementary angles)

Angle A=104 (DAB=104)

Angle D=180-104=76 degrees (angle ADB)

Angle B=60 degrees

Angle C=180-60=120 (DCB)

4 0

2 years ago

Solve for x. Round your answer to the nearest hundredth. 15.56x − 200 < 758.92

Flauer [41]

Answer: x < 61.63

Step-by-step explanation:

15.56x - 200 < 758.92

+200 +200

15.56x < 958.92

/15.56 /15.56

x < 61.63

5 0

3 years ago

Evaluate the indefinite integral. <br> integar x4/1 + x^10 dx

ivann1987 [24]

Answer:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

Step-by-step explanation:

Given

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Required

Integrate

We have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Let

$u = x^5$

Differentiate

$\frac{du}{dx} = 5x^4$

Make dx the subject

$dx = \frac{du}{5x^4}$

So, we have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

$\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}$

$\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du$

Express x^(10) as x^(5*2)

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du$

Rewrite as:

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du$

Recall that: $u = x^5$

$\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du$

Integrate

$\frac{1}{5} * \arctan(u) + c$

Substitute: $u = x^5$

$\frac{1}{5} * \arctan(x^5) + c$

Hence:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

7 0

2 years ago

How many fifths is 7?

Harlamova29_29 [7]

7 is the same thing as 7/1
we can multiply 7/1 by 5/5
which is 35/5

There are 35 fifths in 7

Hope it helps

7 0

3 years ago