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vampirchik [111]
2 years ago
7

Pls help !!! pleaseee.

Mathematics
1 answer:
ladessa [460]2 years ago
8 0
I guess B. That statement is grammatically incorrect.
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Lets interpret Z with M trials. First we have M trials, each trial can be a success or not. The number of success is called N. Each trial that is a success becomes a trial, and if it is a success it becomes a success for Z. Thus, in order for a trial to be successful, it needs first to be successful for the random variable N (and it is with probability q), and given that, it should be a success among the N trials of the original definition of Z (with probability p).

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