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Rufina [12.5K]
3 years ago
6

Which could be the name of a point ?

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0
It should be the 3 ons
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Pls answer both.........
ivanzaharov [21]

The value of x is 3. The correct option is the third option- 3

The width of the backyard is 9 yards. The correct option is the first option-  9 yards

<h3>Perimeter of a Rectangle </h3>

From the question, we are to determine the value of x

13.

Perimeter of a rectangle = 2 (l + w)

Where l is the length

and w is the width

From the given information,

Perimeter = 24 cm

In the given diagram,

l = 3x cm

w = 3 cm

Thus,

24 = 2(3x + 3)

24 = 6x + 6

6x = 24 - 6

6x = 18

x = 18/6

x = 3

Hence, the value of x is 3. The correct option is the third option- 3

14.

From the given information,

The width of the yard is 3 less than 4 times the length

That is,

w = 4l - 3 --------- (1)

Also,

Perimeter = 24 yards

∴ 24 = 2(l + w) ---------- (2)

Put equation (1) into (2)

24 = 2(l + w)

24 = 2(l + 4l - 3)

24 = 2(5l - 3)

24 = 10l - 6

10l = 24 + 6

10l = 30

l = 30/10

l = 3 yards

Substitute the value of l into equation (1) to get w

w = 4l - 3

w = 4(3) - 3

w = 12 - 3

w = 9 yards

Hence, the width of the backyard is 9 yards. The correct option is the first option-  9 yards

Learn more on Perimeter of a rectangle here: brainly.com/question/24571594

#SPJ1

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2 years ago
True or False? When listing the elements of a set, you enclose them in curly
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I believe this problem is true.

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4 years ago
Best grocery sells 5lb of salmon for $100. Fresh grocery’s sells 3 lb of salmon for $63. What is the unit price of salmon at eac
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Step-by-step explanation:

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3 years ago
Find the value of yy in each equation. Explain how you determined the value of yy.
SOVA2 [1]

Answer:

a) 2

b) 5

c) -1

d) x

Step-by-step explanation:

We know the properties of log function as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = \log(A)+\log(B)

3) log(aᵇ) = b × log(a)

also,

4) \log_b(a)=\frac{\log(a)}{\log(b)}

Given:

a. y = log₂(2²)

thus, using 3

y = 2log₂(2)

or using 4

y = 2 × \frac{\log(2)}{\log(2)}

or

y = 2 × 1 = 2

b. y = log₂(2⁵)

thus, using 3

y =  5 × log₂(2)

or using 4

y = 5 × \frac{\log(2)}{\log(2)}

or

y = 5 × 1 = 5

c. y = log₂(2⁻¹)

thus, using 3

y =  -1 × log₂(2)

or using 4

y = -1 × \frac{\log(2)}{\log(2)}

or

y = -1 × 1 = -1

d. y = log₂(2ˣ)

thus, using 3

y =  x × log₂(2)

or using 4

y = x × \frac{\log(2)}{\log(2)}

or

y = x × 1 = x

4 0
4 years ago
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