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Makovka662 [10]
3 years ago
9

Please answer please

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

<BAC = <DEC = 30°

<BCA = <DCE = 70°

<CDE (or m<D) = 180° - <DEC - <DCE

<CDE = 180° - 30° - 70°

<CDE = 80°

The number that belongs in the green box is 80

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What is x? -3(2x-7)+5=2x-9
vitfil [10]

Answer:

x=4.375

Step-by-step explanation:

-3(2x-7)+5=2x-9

-6x+21+5=2x-9

-6x+26=2x-9

-6x-2x+26=2x-2x-9

-8x+26=-9

-8x+26-26=-9-26

-8x=-35

-8x/-8=-35/-8

x=4.375

4 0
3 years ago
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Janet has $60. If tax is 5%, will she have enough money left over to purchase a $12 movie ticket?
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No she will not have enough money
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Evaluate 2/4 _ 8z + 2 (z - 5)
SIZIF [17.4K]
Let's see....

Let's first simplify step-by-step.

2/4 - 8z + 2(2-5)

= 1/2 + - 8z + -6

Combine Like Terms:

= 1/2 + -6

= (- 8z) + (1/2 + -6)

=(- 8z) + (1/2 + -6)

= - 8z + -11/2
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Our answer:

= - 8z + -11/2

Hope This Helps!!!!!!!!
6 0
3 years ago
Find the mean, variance &amp;a standard deviation of the binomial distribution with the given values of n and p.
MrMuchimi
A random variable following a binomial distribution over n trials with success probability p has PMF

f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1

The mean is given by the expected value of the distribution,

\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}
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\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}

The remaining sum has a summand which is the PMF of yet another binomial distribution with n-1 trials and the same success probability, so the sum is 1 and you're left with

\mathbb E(x)=np=126\times0.27=34.02

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\mathbb V(X)=125\times0.27\times0.73=24.8346

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\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834
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