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3 years ago

Please answer please

Mathematics

1 answer:

Murrr4er [49]3 years ago

3 0

<BAC = <DEC = 30°

<BCA = <DCE = 70°

<CDE (or m<D) = 180° - <DEC - <DCE

<CDE = 180° - 30° - 70°

<CDE = 80°

The number that belongs in the green box is 80

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GEOMETRY ONE QUESTION PLZ HELP

earnstyle [38]

Segment addition postulate
Substitution
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Simplification, or Adding like terms
Subtraction property
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4 years ago

Ill give brainliestetfgeyhe on other question too!! PLS ANSWER I CANT GO TO SUMMER SCHOOL

JulsSmile [24]

Answer:

8 grams

Step-by-step explanation:

The balance is in equilibrium, so the weights of the two sides are equal.

Let the weight of a square be s.

Left side: 2s + 4

Right side: s + 3(4) = s + 12

The weights are equal, so we set the two expressions equal.

2s + 4 = s + 12

s = 8

Answer: The weight of a square is 8 grams.

Question 2: The first step was the combine the like terms; in this example he is subtracting the 3x on both sides of the =.

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3 years ago

Read 2 more answers

What is the value of x? please help me! A. 43 B. 62 C. 105 D. 115

Valentin [98]

Answer:

Step-by-step explanation:

x is the exterior angle of angle EFG while EFG = 180 - 62 - 43 = 75

—> x = 180 - 75 = 105

6 0

2 years ago

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago

E U F {2,4,6,8,} true or false

lesya [120]

Tbh i think its true not 100%

4 0

3 years ago