Question

Select the correct answer from each drop-down menu.

Answer 1

Answer:

1.Second equation

2.First equation

3.4

4. is the

Step-by-step explanation:

We are given that two system of equations

System A:$x-y=3$ (Equation I )

$-2x+4y=-2$  ( Equation II)

And solution (5,2)

System B:$x-y=3$  (Equation I)

$2x=10$  ( equation II)

We have to fill correct value in the blank space

Equation one of system A is multiplied by 4 then we get

$3x-4y=12$  (Equation III)

Adding second equation of system A and equation III

Then we get $2x=10$

Solving equations of system B

We get x=$\frac{10}{2}=5$

Substitute x= 5 in equation I of system B then we get

$5-y=3$

$y=5-3=2$

Hence, the solution of system B is (5,2).

Hence, to get system B , the second equation in system  A is replaced by the sum  of that equation   and equation I  is multiplied by 4 .The solution to system B is the same as the solution of system A.

Answer 2

Answer:

To  get system B, the SECOND equation in system A was replaced by the sum of that equation and the FIRST equation multiplied by FOUR. The solution to system B IS de same as the solution to system A

Step-by-step explanation:

x-y=3  equation 1

-2x+4y=-2   equation 2

so, multiplying by four the equation 1 we have

4x-4y=12   equation 3

later sum equation 3 and equation 2 we have

2x=10