Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Given:
The vertex of a triangle MNP are M(-4, 6), N(2, 6), and P(-1, 1).
The rule of dilation is:
The image of triangle MNP after dilation is M'N'P'.
To find:
The coordinates of the endpoints of segment M'N'.
Solution:
The end points of MN are M(-4, 6) and N(2, 6).
The rule of dilation is:
Using this rule, we get
And,
The endpoints of M'N' are M'(-6, 9) and N'(3, 9).
Therefore, the correct option is B.
45
50
You have to add 25 for each one so you get the answer
To solve the problem, get the
percentage of each test by multiplying the score and the percentage then add it all up:
82 * .25 (highest test grade) + 65* .15 (lowest test grade) +
71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework
grade)
= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number
