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stiv31 [10]
4 years ago
14

60 POINTS PLEASE HELP FAST

Mathematics
2 answers:
BartSMP [9]4 years ago
6 0

Original equation: 9(8j + 2 +j)


1st use Distributive property:

Multiply 9 by each term in the parenthesis:

72j + 18 + 9j


2nd use Addition Property to combine like terms:

81j +18



patriot [66]4 years ago
3 0

Answer: With the distributive property you get 72j+18+9j, with the addition property you get 9(9j+2)


Step-by-step explanation: The first way to do this is to distribute the nine among the numbers in the parentheses. Nine into 8j equals 72j. Nine into 2 equals 18. 9 into j equals 9j. Then the problem would be 72j+18+9j. The next answer would be to use the addition property. 8j+j equals 9j. Then there would be the 2, so you would have 9(9j+2)


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Georgia [21]
So the “certain number” will be S.
Since 2width + 2length, the first part would be 2 times 2 which is 4
The length is S - 3
We then have to multiply this by 2
So it is 2(S-3) which is 2S-6
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8 0
4 years ago
The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times
mafiozo [28]
  • Answer:

<em>a = 30°</em>

<em>b = 70°</em>

<em>c = 80°</em>

  • Step-by-step explanation:

<em>Hi there ! </em>

<em />

<em>a ; b ; c = angles</em>

<em>a + b + c = 180°</em>

<em>b + c = 5a</em>

<em><u>replace (b + c)</u></em>

<em>a + (b + c) = 180</em>

<em>a + 5a = 180</em>

<em>6a = 180</em>

<em>a = 30°</em>

<em />

<em>b + c = 180 - a</em>

<em>b + c = 150</em>

<em>c = b + 10</em>

<em><u>replace c</u></em>

<em>b + (b + 10) = 150</em>

<em>2b = 150 - 10</em>

<em>2b = 140</em>

<em>b = 70°</em>

<em>c = b + 10</em>

<em>c = 80°</em>

<em>Good luck !</em>

3 0
3 years ago
Which fraction is closest to zero? 8/12 5/8 6/10 2/3
Triss [41]

Answer:

8/12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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Alex
5/8 is way greater then 1/5

7 0
3 years ago
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Stuck, help please !
Olin [163]

Use the fundamental trigonometric equation

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To rewrite the equation as

1-\cos^2(x) = 1-\cos(x)

Subtract 1 from both sides:

-\cos^2(x) = -\cos(x)

Add \cos^2(x) to both sides:

\cos^2(x) - \cos(x) = 0 \iff \cos(x)\left(\cos(x)-1\right)=0

A multipication is zero if and only if one of the factors is zero. So, the solutions are given by

\cos(x)=0 \iff x=\dfrac{\pi}{2}+k\pi,\quad k \in \mathbb{Z}

or

\cos(x)-1=0 \iff \cos(x)=1 \iff x=2k\pi,\quad k \in \mathbb{Z}

5 0
4 years ago
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