Answer: About 3.14 inches
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
No , because it doesn’t have a pattern . For example put the numbers in a chart 1+3 = 4 , -1+3 =2 , 3+7=10 , 5+11=16 , there’s no pattern
Z=118 as vertically opposite angles are the same
x= (8x-50)
Answer:
If the arrow is pointing to the -2, that’s the constant.
If the arrow is pointing at x, that’s the variable.
If the arrow is pointing at 3, that’s the coefficient.
