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Delicious77 [7]
3 years ago
6

HELP ME ME THANKSssssssssssfijnwijpmcrifljc

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0

Answer:

The volume of the cylinder is 5, 024 cm cubed (the last option)

Step-by-step explanation:

V=\pi r^{2} h\\V=3.14(8^{2} )(25)\\V=3.14(64)(25)\\V=200.96(25)\\V=5024

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Find the probability of the following events , when a dice is thrown once:
Fudgin [204]

Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

Favourable cases for a prime number are 2,3,5,

i.e., n(A)=3

Hence P(A)=n(A)n(S)=36=12

(b) Let A be an event ''getting a number between 3 and 6''.

Favourable cases for events A are 4 or 5.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(c) Let A be an event ''a number greater than 4''.

Favourable cases of events A are 5, 6.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(d) Let A be the event of getting a number at most 4.

∴ A={1,2,3} ⇒ n(A)=4,n(S)=6

∴ Required probability =n(A)n(S)=42=23

(e) Let A be the event of getting a factor of 6.

∴ A={1,2,36} ⇒ n(A)=4,n(A)=6

∴ Required probability =46=23

(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

i.e., n(A)=5

Hence P(A)=n(A)n(S)=536

(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

P(A)=n(A)n(S)=636=16

(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

i.e., n(A)=4

P(A)=n(A)n(S)=436=19

(iii) We have, n(S) = 36

(a) Let A be an event ''a sum less than 7'' i.e., 2,3,4,5,6.

Favourable cases for a sum less than 7 ar

7 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME WITH MY MATH !!!​
kompoz [17]

Answer:

4√41

Step-by-step explanation:

From the Euclidean theorem y^2 = 16 × 41 ➡ y^2 = 656 and y = 4√41

5 0
3 years ago
Three subtracted from 5 x a number is -128. what is that number
omeli [17]

5-3x=-128

LHS = RHS

(5 - 3) x A = -128

( 2 ) x A = -128

2A / 2 = -128 / 2

A = -64

3 0
2 years ago
Y+2=2/5(x+6) write in standard form​
icang [17]

y+2=(2/5)(x+6)

5(y+2)=2(x+6)

5y+10=2x+12

-2x+5y+10-12=0

-2x+5y-2=0

2x-5y+2=0

8 0
2 years ago
How do you write 6,900 in scientific notation?<br> * 10
saw5 [17]

Answer:

6.9 x 103

Step-by-step explanation:

6 0
3 years ago
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