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Mumz [18]
3 years ago
12

HELP ME PLEASE ITS IMPORTANT !!!

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

4 hours = 4(60)=240min

2 hours = 2(60)=120min

120<=x<=240

f(x)=1.20||x/2||

So your answer is :

F(X)=1.20||x/2||, if 120<= x<= 240

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Find the area of the region between the curve y= 2ln(x) and the horizontal axis for 1&lt;= x &lt;= 4
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Answer:

5.09 units

Step-by-step explanation:

Given equation

y=2\ln x=f(x) in the interval 1\le x\le 4

So we integrate y in the given interaval

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Let us integrate \ln x first.

let

u=\ln x, dv=dx

du=\dfrac{1}{x}, v=x

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Using integration by parts we get

uv-\int vdu

=x\ln x-\int x\dfrac{1}{x}dx

=x\ln x-dx

=x\ln x-x+C

So here

\int f(x)=2\int\limits^4_1 {\ln x}dx\\ =2(x\ln x-x)_1^4\\ =2[(4\ln 4-4)-(1\ln 1-1)]\\ =2[4\ln 4-4+1]\\ =5.09\ units

The area of the the region between the curve and horizontal axis is 5.09 units.

5 0
3 years ago
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crimeas [40]

Answer:

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Step-by-step explanation:

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