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dusya [7]
2 years ago
14

Please help, my computer is about to die and this is due in a few minutes. Will mark brainlist if correct.

Mathematics
1 answer:
lidiya [134]2 years ago
3 0

Answer:

x = 1.5

Step-by-step explanation:

Here, we want to solve for the value of x

By using the tangent from the same point theorem, we have it that;

lh^2 = lj * lk

1^2 = (0.5) * (0.5 + x)

1 = 0.5x + 0.25

1-0.25 = 0.5x

0.5x = 0.75

x = 0.75/0.5

x = 1.5

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Can someone help me will mark brainlist
Nana76 [90]

Answer:

D) -4, 0

Step-by-step explanation:

find common difference.

the common difference appears to be +4 as you must add 4 to -12 to get to -8

now we find the missing terms.

the previous term of the first missing term is -8

if the common difference is +4 then the next term would be -8 + 4 = -4

the term after that would be -4 + 4 = 0

the two missing terms are -4 and 0

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2 years ago
Find the GCF of 27x^2 and 45x^3y^2
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Step-by-step explanation:

27x² = 3*3*3*x*x

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Now

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3 years ago
A model of an airplane is built using the ratio of similarity 1 to 50. The airplane is 60feet long. What is the length of the mo
Whitepunk [10]

Answer:

1.2 feet long

Step-by-step explanation:

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3 years ago
If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v
pochemuha

Answer:

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = 5000(1 - \frac{1}{40}t )^2  , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = 2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )

V'(t) = 2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )

When we simplify the above, we get

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If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

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Evaluate log2/3 (4/9)​
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Answer:

2

Step-by-step explanation:

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