in triangle ABC the measure of angle B is 24° more than three times the measure of angle a the measure of angle C is 51° more th
an the measure of angle a the measures of the three angles in a triangle most total 180° find the measure of each angle
1 answer:
M∠A = x
m∠B = 3x+24
m∠C = x + 51
x + 3x+24 + x + 51 = 180
5x + 75 = 180
5x = 180 - 75
5x = 105
x = 105/5
x = 21
m∠A = x = 21°
m∠B = 3x+24 = 3*21 + 24 = 87°
m∠C = x + 51 = 21 + 51 = 72°
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