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3 years ago

FIND THE VALUE OF x³=-8 A ±4 B ±2 C-2 D-4

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

Answer:

x=-2

Step-by-step explanation:

In this kind of question,we will have to be extra careful to prevent errors or mistake.reason for the errors and mistake is that there is a negative sign in front of the 8...so any solution must ensure to involve the negative sign...or else the final answer will be discarded...

So back to the question

X^3=-8

Which means that the cube of x is 8 and we are to solve for x, therefore to solve this question...we will have to cube root both sides...why

So as to eliminate the cube on x...

Ok how,cube root of x^3 can also be written as x^3×1/3 which gives x

And cube root of -8 will be either 8^1/3 or3√-8

And the answer is-2

To confirm the answer we can say -2×-2×-2=-8

So the final answer is -2

Therefore x=-2

alexandr1967 [171]3 years ago

5 0

Answer:

$C.) \: \: \: - 2$

Step-by-step explanation:

$({ - 2})^{3} = - 8$

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A principal amount of $4,700 is deposited into an account paying interest at a rate of 3%, continuously compounded. What will be

Ronch [10]

The account balance after 3 years if the interest is compounded continuously is $5,142.62

<h3>How to find compound interest?</h3>

Principal, P = $4,700
Time,t = 3 years
Interest rate, r = 3%

r = 3/100

r = 0.03 rate per year,

A = Pe^rt

A = 4,700.00(2.71828)^(0.03)(3)

= 12,775.916^0.09

A = $5,142.62

Therefore, the account balance after 3 years if the interest is compounded continuously is $5,142.62

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2 years ago

You toss a pair of dice. (a determine the number of possible pairs of outcomes. you toss a pair of dice. (a determine the number

Eduardwww [97]

(a) $^{6}C_1 * ^{6}C_1 = 36$ different possibilities
(b) $P(even die 1): \frac{1}{2}$
$P(even die 2): \frac{1}{2}$

So, there is a 1 in 4 chance that both dice will show an even.

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3 years ago

A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has

bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] = 1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0

3 years ago

What two numbers multiply to 75 and add too -20

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

-15 times -5 = 75

-15 + -5 = -20

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3 years ago

In the diagram below DE is parallel to XY. What is the value of y?

kirza4 [7]

this would be 94 hope it helps

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4 years ago

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