Question

With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph to explain the relationship between the total amount money spent on bowling in a year and the number

Answer 1

Answer:

Part a) $a=4g+10$ (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

The complete question is

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

$a=mg+b$

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

$m=\ 4\ per\ game$

$b=\ 10$

substitute

$a=4g+10$

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> $a=4(0)+10=\ 10$

For g=1 ----> $a=4(1)+10=\ 14$

For g=2 ----> $a=4(2)+10=\ 18$

For g=3 ----> $a=4(3)+10=\ 22$

For g=4 ----> $a=4(4)+10=\ 26$

The table is

$\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]$

Part c) Use the values from your table to draw a graph

we have the ordered pairs

$(0,10),(1,14),(2,18),(3,22),(4,26)$

Plot the ordered pairs and join them to graph the line

The graph in the attached figure