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ahrayia [7]
3 years ago
14

Simplify 7^2x^-3y/49x^-3y^-2

Mathematics
2 answers:
Mrac [35]3 years ago
5 0
This is the answer I got
x(xy-7)^2

olya-2409 [2.1K]3 years ago
4 0
\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3} \times  \frac{1}{y^2} } \\ \\  \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times  \frac{y^2}{49x^{-3}} \\ \\  \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\

The answer is: y^3.
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903 offices

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Step-by-step explanation:


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6 0
2 years ago
Given: Triangle ABC, mmBC=24 cm, line segment AL- &lt; bisector
Furkat [3]

The value of line AL is 21. 51cm

<h3>How to determine the length</h3>

To find line AL,

Using

Sin α = opposite/ hypotenuse to find line AB

Sin 90 = x/ 24

1 = x/24

Cross multiply

x = 24cm

Now, let's find line AC

Sin angle B = line AC/24

Note that to find angle B

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But angle B = 2 Angle A

x + 2x + 90 = 180

3x + 90 = 180

3x = 180-90

x = 30°

Angle B = 2 × 30 = 60°

Sin 60 = x/ 24

0. 8660 = x/24

Cross multiply

x = 24 × 0. 8660

x = 20. 78cm

We have the angle of A  in the given triangle to be divide into two by the bisector, angle A = 15°

To find line AL, we use

Cos = adjacent/ line AL

Cos 15 = 20. 78/ line AL

Line AL = 20. 78/ cos 15

Line AL = 20. 78 / 0. 9659

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Learn more about trigonometry ratio here:

brainly.com/question/24349828

#SPJ1

6 0
1 year ago
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