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First, we need to make the equation given to be in the form;
y=mx + b
where m is the slope and b is the intercept
8y - 3x = -8
Add 2x to both-side of the equation
8y = 3x - 8
Divide through the equation by 8
y = 3/8 x -1
comparing the above with y =mx + b
m = 3/8
slope of parallel equations are equal
From the options given the only equation with slope 3/8 is;
y= 3/8 x + 8
The above equation of the line is parallel to 8y - 3x = -8
To solve, you must make one side of the equation equal to zero. We can do this by subtracting 3x on both sides of the equation.
<span>x^2 + 7x = 3x
</span> - 3x -3x
x^2 + 4x = 0.
Then we substitute the equation into the quadratic equation.
Where a = 1 b = 4 and c = 0
We first solve whats inside the square root.
Now we solve for -4 and 4.
Then divide both answer by 2
The division of any by zero is zero
So the answer are x = -4 and x = 0
<span>x^2 + 7x = 3x
</span> - 3x -3x
x^2 + 4x = 0.
Then we substitute the equation into the quadratic equation.
Where a = 1 b = 4 and c = 0
We first solve whats inside the square root.
Now we solve for -4 and 4.
Then divide both answer by 2
The division of any by zero is zero
So the answer are x = -4 and x = 0