Answer:
The differential equation is ![\frac{dx(t)}{dt} = k x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%3D%20k%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
Step-by-step explanation:
From the question we are told that
The number of students are 
The number of student that have contracted the flu is x(t)
The number of student that don't have the flu is mathematically represented as
The rate at which the disease spread is proportional to the number of interactions between students with the flu and students who have not yet contracted it, which can be mathematically represented as
![\frac{dx(t)}{dt} \ \ \ \alpha\ \ \ x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%5C%20%5C%20%5C%20%5Calpha%5C%20%5C%20%5C%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
=>
Answer:
x = 16 and y = 121
Yes, its a long process.
Step-by-step explanation:
vertical angles are congruent given that: we do this
(4x-5)+(4x-5)+y+y=360
or
2(4x-5)+2y=360
divide both sides by 2
(4x-5)+y=180
distribute (there is an invisible 1 beside the parentheses of 4x-5)
4x-5+y=180
add 5 to both sides
4x+y = 185
subtract y from both sides
4x = 185-y
divide both sides by 4
x = (185-y)/4
note that (4x-5) is also EQUAL to (3x+11)
4x-5=3x+11
subtract 3x from both sides
x-5=11
add 5 to both sides
x = 16
Now that we know what x is, we can substitute it in the equation we got from 2(4x-5)+2y=360
Our equation was
x = (185-y)/4
16 = (185-y)/4
Multiply both sides by 4
64 = 185-y
Subtract 185 from both sides
-121=-y
multiply both sides by -1
121 = y
Answer:
The probability that no boats arrive is 
.
Step-by-step explanation:
Poisson distribution:
Poisson distribution is a statistical distribution that helps to find out the probability of a certain is likely occur a specified period of time.
= rate.
Given that, Poisson distribution at a rate of 3 per hour.
= 3
t=2
x=0
The probability that no boats arrive is
B. Hundredths
It goes tenths, hundredths, thousandths
$10.83 because you need to divide 6.50 by .6 to get that answer approximately.
