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My name is Ann [436]
2 years ago
10

(08.01)Angela wants to know how many families in her neighborhood plan to attend the parade. She puts all 120 of the neighborhoo

d addresses in a hat and draws a random sample of 30 addresses. She then asks those families if they plan to attend the parade. She finds that 40% of the families plan to attend the parade. She claims that 40% of the neighborhood families would be expected to attend the parade. Is this a valid inference?
A) Yes, this is a valid inference because the 30 families speak for the whole neighborhood


B)Yes, this is a valid inference because she took a random sample of the neighborhood


C)No, this is not a valid inference because she did not take a random sample of the neighborhood


D) No, this is not a valid inference because she asked only 30 families
Mathematics
1 answer:
Zolol [24]2 years ago
3 0

Using sampling concepts, the correct option regarding the validity of the inference is given as follows:

B) Yes, this is a valid inference because she took a random sample of the neighborhood.

<h3>What is sampling?</h3>

It is a common statistics practice, when we want to study something from a population, we find a sample of this population, which is a group containing elements of a population. A sample has to be representative of the population, that is, it has to involve all segments of the population.

For example:

I want to estimate the proportion of New York state residents who are Buffalo Bills fans. So I ask, lets say, 1000 randomly selected New York state residents whether they are Buffalo Bills fans, and expand this to the entire population of New York State residents. If I had taken 1000 residents just from Buffalo, it would not be a representative sample.

In this problem, all addresses in the neighborhood are considered, hence a random sample was taken and the correct option is given as follows:

B) Yes, this is a valid inference because she took a random sample of the neighborhood.

More can be learned about sampling concepts at brainly.com/question/25122507

#SPJ1

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Round 23.5481 to the nearest thousandth
NemiM [27]

Answer: 23.548

Step-by-step explanation: The thousandths place is 3 places to the right of the decimal point so in this problem, the digit in the rounding place is 8.

The rules of rounding says that if the digit to the right of the rounding place is greater than or equal to 5, we round down but if the digit to the right of the rounding place is less than 5, we round down.

Since the digit to the right of the rounding place, 1, is less than 5, we round down. This means that the digit in the rounding place which is 8 stays the same and we change all digits to the right of 8 to zero.

So we have 23<em>.</em>5480.

Finally, it's important to understand that when rounding decimals, we can drop any zeroes to the right of the decimal point as long as they're also to the right of the rounding place.

This means that 23.5481 rounded to the nearest thousandth is 23<em>.</em>548.

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The students are trying to raise 3.000 but they only have 1200 how much would they need to get to 3000
Serga [27]
1800. 3000-1200=1800
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The answer to this proportion would be X=4
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If you subtract 58 by 14 you will get 44 so thats the answer


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You are choosing between two plans at a discount warehouse. Plan A offers an annual membership fee of $ 90and you pay 30 %of the
Ad libitum [116K]

Answer:

Step-by-step explanation:

We have 2 linear equations, and in both, the amount of merchandise you would have to purchase is "x", the unknown.  We are asked to find that value of x.

The first equation is

C(x) = .30x + 90, which says that the cost of this plan is a fixed $90, and you pay 30% of the manufacturer's cost, x.

The second equation is

C(x) = .80x + 40, which says that the cost of this plan is a fixed $40, and you pay 80% of the manufacturer's cost, x.

If we want to know when the cost of these 2 are equal to each other, we set the equations equal to each other and solve for x:

.3x + 90 = .8x + 40 so

-.5x  = -50 so

x = $100

The cost for each plan will be the same at this value of x, but we will plug in 100 for x in each just to make sure we did it right:

C(100) = .3(100) + 90

C(100) = 30 + 90

C(100) = 120  and

C(100) = .8(100) + 40

C(100) = 80 + 40

C(100) = 120

6 0
3 years ago
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