Question

Find the area of the shape below.

Answer 1

Answer:

 $A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not  give the dimensions of the triangle and the dimensions of the square, I will giveyou  a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

$A_{triangle}=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

And the area of a square can be found with this formula:

$A_{square}=s^2$

Where "s" is the length of any side of the square.

Therefore, the area of the shape will be

 $A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$