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Novosadov [1.4K]
3 years ago
5

Stanley makes a $500 investment and then carefully tracks the value as time goes by. At first, the value of Stanley's $500 inves

tment changes by -$4 each day. After how many days, did value of the investment change by -$28?
Mathematics
1 answer:
mafiozo [28]3 years ago
5 0
You would of taken 28 dollars away after 7 days because if your taking away 4$ each day you just have to figure out 4 times what equals 28 witch is 7

So the answer is 7 days
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A die was rolled eight times. The rolls were 2, 2, 3, 4, 4, 5, 6, and 6. What is the mean absolute deviation for this data? A) 1
adoni [48]

Answer:

The correct option is A:

MAD = 1 + 1/4

Step-by-step explanation:

For a set of N elements {x₁, x₂, ..., xₙ}

The mean is calculated as:

M = \frac{x_1 + x_2 + ... + x_n}{N}

And the mean absolute deviation is calculated as:

MAD = \frac{Ix_1 - MI + Ix_2 - MI + ...+ IX_n - MI}{N}

Here we have the set of 8 elements:

{ 2, 2, 3, 4, 4, 5, 6, 6}

The mean of this set is:

M = (2 + 2 + 3 + 4 + 4 + 5 + 6 + 6)/8 = 4

Then the mean standard deviation is:

MAD = \frac{I2 - 4I + I2 - 4I + I3 - 4I + I4 - 4I + I4 - 4I + I5 - 4I + I6 - 4I + I6 - 4I}{8} = 10/8

If we simplify this, we get:

MAD = 10/8 = 5/4  = (4 + 1)/4 = 4/4 + 1/4 = 1 + 1/4

MAD = 1 + 1/4

The correct option is A.

6 0
2 years ago
Roger has $2, $1 and 50 cent pieces in the ratio of 5:4:2. If 30 of roger’s coins are 50 cent pieces, how many $2 coins and $1 c
rosijanka [135]

Answer:

Step-by-step explanation:

So the ratio is 5:4:2

there are 11 parts to this ratio (5+4+2)

the 5 is for the $2, the 4 is for the $1 and the 2 is for the 50 cents

he has 30 of the 50 cents

so you divide 30 by 2 to get one part of this ratio

1 part of this ratio is equal to 15 coins

multiply 15 by 5 to get the number of $2 coins: 75

multiply 15 by 4 to get the number of $1 coins: 60

add all of those parts together

30+60+75 = 165

If he uses a $1 coin to buy the sundae he will have 75 $2 coins and 59 $1 coins left

however, if he uses two 50 cents coins to buy the sundae he will have 75 $2 coins and 60 $1 coins left

4 0
3 years ago
Read 2 more answers
This is the image yall were asking for
Lubov Fominskaja [6]

Answer:

angle b+54 = 90 degrees

90 - 54 = b

36° = angle b

5 0
3 years ago
Read 2 more answers
A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are
Gelneren [198K]

Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

8 0
3 years ago
Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)
givi [52]

Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

Step-by-step explanation:

Since we have given that

y=x^{8sinx}

By using logarithmic on both sides we get,

log y= 8 sinx. logx

(∵ log(a^m)=m.loga)

Now, differentiating on both sides ,we get,

\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})

\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})

\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

6 0
3 years ago
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