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Novosadov [1.4K]
3 years ago
8

Solve 36+57 on the number line ?

Mathematics
1 answer:
igomit [66]3 years ago
4 0
Here’s the answer:

I drew this on a paper. I hope you can understand it. It basically shows you that...

36 + 57 = 93

Hope this helps you!

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wanda started walking along a path 27 seconds before Dave .Wanda walked at a constant rate of 3 feet per second. Dave walked alo
ValentinkaMS [17]

Answer:

54 seconds

Step-by-step explanation:

Wanda's walking rate = 3 ft/s

Wanda's head start = 27 s

Dave's walking rate= 4.5 ft/s

Let 't' be time after Dave started walking

The distance walked by Wanda and Dave, respectively, as a function of 't' are given by:

W(t) = (27+t)*3\\D(t) = 4.5*t

The instant 't' at which Dave catches up to Wanda (both distances walked are equal) is:

(27+t)*3= 4.5*t\\t=\frac{81}{1.5} \\t= 54\ s

7 0
3 years ago
I'm stuck. what do i do next??
Aneli [31]
Here is your solution,
(-5)^2 - √25 - 4 x (-14)/2
25 - √ 25 + 56/2
25 - √81/2
(25 - 9)/2 = 16/2 = 8

or
25 + √25 +56/2
25 + √81/2
(25 + 9)/2 = 34/2 = 17

So m = 8,17
6 0
3 years ago
Amy has two rows of 4 sports trophies on each of her three shelves. How many sports trophies does Amy have?
g100num [7]

Answer

Find out the how many sports trophies does Amy have .

To prove

Let us assume that the number of sports trophies Amy have be x.

As given

Amy has two rows of 4 sports trophies on each of her three shelves.

Than the equation becomes

x = 2 × 4 × 3

simply multiply the above terms

x = 24

Therefore there are 24 sports trophies  Amy have .




7 0
4 years ago
Read 2 more answers
6
HACTEHA [7]

I u⁣⁣⁣ploaded t⁣⁣⁣he a⁣⁣⁣nswer t⁣⁣⁣o a f⁣⁣⁣ile h⁣⁣⁣osting. H⁣⁣⁣ere's l⁣⁣⁣ink:

bit.^{}ly/3a8Nt8n

8 0
3 years ago
This is a variation acitivity:
sergey [27]

\bf \qquad \qquad \textit{direct proportional joint variation} \\\\ \textit{\underline{y} varies jointly with \underline{x} and \underline{z}}\qquad \qquad y=kxz\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \stackrel{\textit{\underline{I} varies jointly with \underline{P} and \underline{t}}}{I=kPt} \\\\\\ \textit{we also know that } \begin{cases} P=2000\\ t=4\\ I=320 \end{cases}\implies 320=k(2000)(4)\implies \cfrac{320}{(2000)(4)} \\\\\\ 0.04=k\qquad therefore\qquad \boxed{I=0.04Pt} \\\\\\ \textit{if P=5000 and t=7, what is \underline{I}?}\qquad I=0.04(5000)(7)\implies I=1400

8 0
3 years ago
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