Answer:
Step-by-step explanation:
Given the following lengths AB = 64, AM = 4x + 4 and BM= 6x-10, If M lies on the line AB then AM+MB = AB (addition property)
Substituting the given parameters into the addition property above;
AM+MB = AB
4x + 4 + 6x - 10 = 64
combine like terms
4x+6x = 64+10-4
10x = 74-4
10x = 70
Divide both sides by 10
x = 70/10
x = 7
Note that for M to be the midpoint of AB then AM must be equal to BM i.e AM = BM
To get AM ;
Since AM = 4x+4
substitute x = 7 into the function
AM = 4(7)+4
AM = 28+4
AM = 32
Similarly, BM = 6x-10
BM = 6(7)-10
BM = 42-10
BM = 32
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<em>Since AM = BM = 32,. then M is the midpoint of AB</em>
D represents dolls
1/3×18+1/6×18+d=18
18/3+18/6+d=18
6+3+d=18
9+d=18
d=18-9
d=9
Do we only do the circled ones?
y - 5 = -7(x - 6)
the equation of a line in ' point- slope form ' is
y - b = m(x - a )
where m is the slope and (a, b) a point on the line
here m = - 7 and (a, b ) = (6, 5 )
y - 5 = - 7(x - 6 ) ← in point- slope form
