3a^4(2b^6c^3)^2 Can someone help me simplify this?
1 answer:
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The solution is
<em><u>Solution:</u></em>
Let us assume,
<em><u>Given system of equations are:</u></em>
<em><u>Rewrite the equation using "a" and "b"</u></em>
2a - 3b = -5 ------------ eqn 1
4a + 6b = 14 -------------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 2</u></em>
2(2a - 3b = -5)
4a - 6b = -10 ------------- eqn 3
<em><u>Add eqn 2 and eqn 3</u></em>
4a + 6b = 14
4a - 6b = -10
( - ) --------------------
8a = 4
Substitute a = 1/2 in eqn 1
Now let us go back to our assumed values
Substitute a = 1/2 in assumed values
Substitute b = 2 in assumed value
Thus the solution is