The ordered pairs that are located 8 units away from the point (2, 1) are; (-6,1), (10,1), (2,-7) and (2,9)
<h3>Ordered pairs and Distance.</h3>
The ordered pairs which can be 8 units away from the point, (2, 1) are pairs in which case, either x or y coordinates or both are 8 units from the given pair of coordinates (2,1).
Hence, the following pair of coordinates have x or y coordinates which are 8 units away from the x or y coordinates of the given pair of coordinates.
Read more on coordinates;
brainly.com/question/3447129
8) you go up by 2 on the y-axis and over 3 on the x-axis
9) you have to go up 3 on the y-axis and over 2 on the x-axis
But you always have to go over then up
Dilation is either : enlargement or shirking.
Simply you multiply the ordered pair times the dilation vector (Origin-Centered)
D.F = dilation factor;
d.f = 5
C' = d.fC
when you multiply a constant times an ordered pair , it multiples into each of the pair.
C' = 5 ( -5 , 1 ) = ( -25, 5 )
In case you were asked for A' , B' (test yourself before checking)
A' = 5 (-4,3) = ( -20 , 15)
B' = 5 ( 2, 3 ) = ( 10, 15)
Dividing the dilated by the original pair results in the dilation factor
A'/A = (-20/15)/(-4,3) = 5(-4,3)/(-4,3) = 5
Answer
-3
+
+16=0
Step-by-step explanation:
If the part inside the square root is negative, there are imaginary roots. Otherwise they are real.
