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3 years ago

Alex lives 3/10 of a mile from his school. If he walks to and from school each day how far will he walk in a week?

Mathematics

1 answer:

Lina20 [59]3 years ago

4 0

He would walk 3/10 x7 so that would be 21/10 simplify that will be 2 1/10

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An airline runs a commuter flight between Portland, Oregon, and Seattle, Washington, which are 145 miles apart. An increase of 2

pychu [463]

The speed of the airplane is the ratio of the distance to the time

The initial average speed of the airplane is approximately 110.8 mph

Reason:

Given parameters are;

The distance between Portland Oregon and Seattle Washington = 145 miles

The decrease in travel time when the speed is increase by 20 mph = minutes

The initial speed of the airplane, v = Required;

Solution;

$t = \dfrac{145}{v}$

$t - \dfrac{12}{60} = \dfrac{145}{v + 20}$

Therefore;

$\dfrac{145}{v} - \dfrac{12}{60} = \dfrac{145}{v + 20}$

Which gives;

$\dfrac{145}{v + 20} - \dfrac{145}{v} + \dfrac{12}{60} = 0$

Therefore

0.2·v² + 4·v - 2,900 = 0

v ≈ ±110.8 mph

The initial average speed of the airplane, v≈ ± 110.8 mph

Learn more here:

brainly.com/question/11365874

4 0

2 years ago

0.135 written as a fraction

OleMash [197]

Answer:

135/1000

27/200

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What are the formulas for total surface area of 3D shapes ?

wel

To find the surface area of a rectangular prism or cube, you would do height*width*2+height*length*2+length*width*2.

4 0

3 years ago

Find the measure of each missing angle explain work

BartSMP [9]

Angle 1: 52 degrees
angle 2: 79 degrees
angle 3: 38 degrees

explanation:
angle 1: 180 - 90 - 38 = 52
angle 2: 180 - 63 - 38 = 79
angle 3: 90 - 52

6 0

2 years ago

Rewrite 2tan3x in terms of tanx

blsea [12.9K]

$2\tan3x=2\tan(2x+x)=\dfrac{2\tan2x+2\tan x}{1-\tan2x\tan x}$

Use the same identity to expand $\tan2x$ .

$\tan2x=\tan(x+x)=\dfrac{\tan x+\tan x}{1-\tan x\tan x}=\dfrac{2\tan x}{1-\tan^2x}$

$\implies2\tan3x=\dfrac{2\dfrac{2\tan x}{1-\tan^2x}+2\tan x}{1-\dfrac{2\tan x}{1-\tan^2x}\tan x}$
$2\tan3x=\dfrac{2\tan x\left(\dfrac2{1-\tan^2x}+1\right)}{1-\dfrac{2\tan^2x}{1-\tan^2x}}$
$2\tan3x=\dfrac{2\tan x\left(2+1-\tan^2x\right)}{1-\tan^2x-2\tan^2x}$
$2\tan3x=\dfrac{2\tan x(3-\tan^2x)}{1-3\tan^2x}$

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3 years ago