We know that the width of the wall = 13.3 feet
We also know that the number of stripes to be painted = 14
⇒ Width of one stripe = ![\frac{Width of Wall}{Total Number of Stripes to be Painted}](https://tex.z-dn.net/?f=%5Cfrac%7BWidth%20of%20Wall%7D%7BTotal%20Number%20of%20Stripes%20to%20be%20Painted%7D)
⇒ Width of one stripe = ![\frac{13.3}{14}](https://tex.z-dn.net/?f=%5Cfrac%7B13.3%7D%7B14%7D)
⇒ Width of one stripe = 0.95 feet
Hence, the width of one stripe would be 0.95 feet
Answer:
![\frac{1}{-9}tan \frac{1}{x^9} + c](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B-9%7Dtan%20%5Cfrac%7B1%7D%7Bx%5E9%7D%20%2B%20c)
Step-by-step explanation:
The question requires addition information. Below is how the question should be rightly stated.
------(1)
Using substitution method,
We are given
-------(2)
⇒ ![u =x^{-9}](https://tex.z-dn.net/?f=u%20%3Dx%5E%7B-9%7D)
Differentiating u with respect to x,
![\frac{du}{dx} = -9x^{-9-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bdu%7D%7Bdx%7D%20%3D%20-9x%5E%7B-9-1%7D)
![\frac{du}{dx} = -9x^{-10}](https://tex.z-dn.net/?f=%5Cfrac%7Bdu%7D%7Bdx%7D%20%3D%20-9x%5E%7B-10%7D)
Making dx the subject of the equation
![dx =\frac{du}{-9x^{-10}}](https://tex.z-dn.net/?f=dx%20%3D%5Cfrac%7Bdu%7D%7B-9x%5E%7B-10%7D%7D)
---------(3)
Substituting the values of u from equation (2) and dx from equation (3) into equation (1)
![\int\limits {\frac{sec^{2}u}{x^{10}}} . \frac{x^{10}}{-9} \, du](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%5Cfrac%7Bsec%5E%7B2%7Du%7D%7Bx%5E%7B10%7D%7D%7D%20.%20%5Cfrac%7Bx%5E%7B10%7D%7D%7B-9%7D%20%5C%2C%20du)
![\int\limits {\frac{sec^{2}u}{-9}} \, du](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%5Cfrac%7Bsec%5E%7B2%7Du%7D%7B-9%7D%7D%20%5C%2C%20du)
substituting the value of u
Scale factor= largest length/smallest length then simplify
Answer:
the answer is y=32x+198
Step-by-step explanation:
y-y=m(x-x1)
y-6=32(x-(-6))
y-6=32x+192
+6 +6
y=32x+198