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Finger [1]
4 years ago
13

Is the figure a rectangle? Explain.

Mathematics
1 answer:
Sphinxa [80]4 years ago
7 0
Here is the first sign that should tell you this isn't a rectangle. 

d=_/w^2+l^2 is the equation to solve the diagonal of a rectangle

if you plug in 21 and 20, d would equal 29 not 28 so for that reason alone it is not a rectangle.

I am about 90% sure the correct answer is B. I hope this helps let me know if I was right.

Option B!

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State which of the following sets of ordered pairs represent a function.
stich3 [128]
A function is an equation that has only one answer for y for every x. This means that:

Set A and Set C are functions because their y values don’t repeat.

Set B is NOT a function because the 2 in the y values repeats twice.

Hope I helped!
8 0
3 years ago
Consider these numbers, ordered from least to greatest. Negative 1.8, negative 1 and one-fourth, negative 0.2, blank, one-half,
Norma-Jean [14]

Answer:

10%

-0.1

1/4

Step-by-step explanation:

Complete question

Consider these numbers, ordered from least to greatest. Negative 1.8, negative 1 and one-fourth, negative 0.2, blank, one-half, 90 percent A number line going from negative 2 to positive 1. Which values could correctly fill in the blank? Select all that apply. 10% 1 -0.1 -1 One-fourth

step-by-step explanation

On the number line, numbers increase from left to right.

The blank is between -0.2 and 1/2.

Only numbers greater than -0.2 and less than 1/2 can fill the blank.

Range = -0.2<x<1/2

From the values given,

1) 10% = 10/100 = 1/10 = 0.1

-0.2<0.1<1/2

2) -0.2<1

But, 1>1/2

3) -0.2<-0.1<1/2

4) -0.2>-1

5) -0.2<1/4<1/2

Therefore, only 10%, -0.1, and 1/4 can fill in the blank correctly because they satisfy the range -0.2<x<1/2

5 0
3 years ago
Read 2 more answers
Determine the general solution of:<br><br> sin 3x - sin x = cos2x
SpyIntel [72]
Sin³ x-sin x=cos ² x

we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
              1     2      1      0
       -1         -1      -1                       z=-1
--------------------------------------
              1     1       0                       z=-1

Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
6 0
3 years ago
Based on the quadratic model, what was the approximate number of workers that were hired during the seventh year?
IrinaVladis [17]
You need to show quadratic model, in order for me to answer.
7 0
3 years ago
From this diagram, select the
Makovka662 [10]

Answer:

<h3>Line L is parallel to N </h3>

angle 1 is equal to angle 4 ( vertically opposite angles)

if angle 1 is congruent to angle 8

then angle 4 is also congruent to angle 8

then slope of line L and n is equal

that is L is parallel to n

3 0
2 years ago
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