Can you show me the options?
Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,
![cos\alpha= 5/13](https://tex.z-dn.net/?f=cos%5Calpha%3D%205%2F13)
[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= ![+ or -\sqrt{1-(cos\beta) ^{2}](https://tex.z-dn.net/?f=%2B%20or%20-%5Csqrt%7B1-%28cos%5Cbeta%29%20%5E%7B2%7D)
[by general trigonometry formula:
]
so if
, we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
Any equation of the form
y = kx + b,
with b different from zero
Step-by-step explanation:
For example
y = 5*x +3
cannot be written in the form
y = k*x, because there is a term that shifts the graph upwards.
Answer:
Integers are always closed under subtraction, addition and multiplication, not division though. Hope this helped! :D
Step-by-step explanation: