Answer:
The equations represent circles that result in the same graph.
Step-by-step explanation:
we have

Divide by -10 both sides
-----> equation A
This is the equation of a circle centered at origin with radius 
and
Divide by 5 both sides
-----> equation B
This is the equation of a circle centered at origin with radius 
equation A and equation B are equal
therefore
The system has infinite solutions, because the equations represent circles that result in the same graph.
B the set of input values for the function.
Answer:
x = 8sqrt3
y=8
Step-by-step explanation:
cos60=y/16
y=16cos60
y=16x1/2
y=8
sin60=x/16
x=16sin60
x=(16sqrt3)/2
x=8sqrt3
9514 1404 393
Answer:
x = 10·cos(θ) -4·cot(θ)
Step-by-step explanation:
Apparently, we are to assume that the horizontal lines are parallel to each other.
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
If the junction point in the middle of AB is labeled X, then we have ...
sin(θ) = 4/BX ⇒ BX = 4/sin(θ)
cos(θ) = x/XA ⇒ XA = x/cos(θ)
Then ...
BX +XA = AB = 10
Substituting for BX and XA using the above relations, we get
4/sin(θ) +x/cos(θ) = 10
Solving for x gives ...
x = (10 -4/sin(θ))·cos(θ)
x = 10·cos(θ) -4·cot(θ) . . . . . simplify
_____
We used the identity ...
cot(θ) = cos(θ)/sin(θ)