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777dan777 [17]
4 years ago
14

Shya works part-time at a gift-wrapping. The store sells wrapping paper rolls and package of wrapping rolls. There are a total o

f 125 rolls and package. Each roll costs $3.50 and each package costs $2.25. The total of all of the rolls and package is $347.50  . How many rolls of wrapping paper are there?
Mathematics
1 answer:
Neko [114]4 years ago
7 0
The way you wrote the question was a bit confusing. Also, there are two variables here. To find the one variable (the number of rolls of wrapping paper) we need to find the number of packages.
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Consider the following system of equations. -10x2-10y2=-300 5x2+5y2=150 Which statement describes why the system has infinite so
scoundrel [369]

Answer:

The equations represent circles that result in the same graph.

Step-by-step explanation:

we have

-10x^{2}-10y^{2}=-300

Divide by -10 both sides

x^{2}+y^{2}=30 -----> equation A

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

and

5x^{2}+5y^{2}=150

Divide by 5 both sides

x^{2}+y^{2}=30 -----> equation B

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

equation A and equation B are equal

therefore

The system has infinite solutions, because the equations represent circles that result in the same graph.

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3 years ago
At 6:00 A.M the temperature was 25 F.At 9:00 P.M the temperature was -13F,What was the difference in the temperature?
Alex73 [517]
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5 0
3 years ago
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What is meant by the term 'domain'?
damaskus [11]
B the set of input values for the function.
4 0
3 years ago
Please help I am struggling please
Katen [24]

Answer:

x = 8sqrt3

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Step-by-step explanation:

cos60=y/16

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Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

  sin(θ) = 4/BX   ⇒   BX = 4/sin(θ)

  cos(θ) = x/XA   ⇒   XA = x/cos(θ)

Then ...

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Substituting for BX and XA using the above relations, we get

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Solving for x gives ...

  x = (10 -4/sin(θ))·cos(θ)

  x = 10·cos(θ) -4·cot(θ) . . . . . simplify

_____

We used the identity ...

   cot(θ) = cos(θ)/sin(θ)

6 0
3 years ago
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