![\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\ \\ \text{we know that the product of LCM and HCF of any two numbers is equal}\\ \text{to the product of the numbers. that is}\\ \\ \text{HCF}\times \text{ LCM}=p\times q\\ \\ \Rightarrow 59 \times \text{LCM}=590\\ \\ \Rightarrow \text{LCM}=\frac{590}{59}\\ \\ \Rightarrow \text{LCM}=10\\ \\ \text{for any two natural numbers, their Least Common Multiple (LCM) is always}](https://tex.z-dn.net/?f=%20%5Ctext%7BLet%20the%20product%20of%20two%20natural%20numbers%20p%20and%20q%20is%20590%2C%20and%20their%20HCF%20is%2059%7D%5C%5C%0A%5C%5C%0A%5Ctext%7Bwe%20know%20that%20the%20product%20of%20LCM%20and%20HCF%20of%20any%20two%20numbers%20is%20equal%7D%5C%5C%0A%5Ctext%7Bto%20the%20product%20of%20the%20numbers.%20that%20is%7D%5C%5C%0A%5C%5C%0A%5Ctext%7BHCF%7D%5Ctimes%20%5Ctext%7B%20LCM%7D%3Dp%5Ctimes%20q%5C%5C%0A%5C%5C%0A%5CRightarrow%2059%20%5Ctimes%20%5Ctext%7BLCM%7D%3D590%5C%5C%0A%5C%5C%0A%5CRightarrow%20%5Ctext%7BLCM%7D%3D%5Cfrac%7B590%7D%7B59%7D%5C%5C%0A%5C%5C%0A%5CRightarrow%20%5Ctext%7BLCM%7D%3D10%5C%5C%0A%5C%5C%0A%5Ctext%7Bfor%20any%20two%20natural%20numbers%2C%20their%20Least%20Common%20Multiple%20%28LCM%29%20is%20always%7D%20)
![\text{greater than their HCF.}\\ \\ \text{but here we can see that }LCM](https://tex.z-dn.net/?f=%20%5Ctext%7Bgreater%20than%20their%20HCF.%7D%5C%5C%0A%5C%5C%0A%5Ctext%7Bbut%20here%20we%20can%20see%20that%20%7DLCM%20%3CHCF%20)
Hence there is no such natural numbers exist.
.
I converted it into decimal form with a calculator and got approximately 48.9898
And if you round that, you will get the 49, which fits the inequality of
45<
< 50 since it becomes 45 < 49 < 50 which is true
Answer: 5 lunches for $71 is better
57/4=14.25
71/5=14.2
Answer: Linear
Step-by-step explanation: A linear function can have different rates of change over different intervals.
(I don't know if this is correct, but this is my understanding of it.)
Answer:
183.375 in2
Step-by-step explanation:
I did it on study island.