An expression which gives the number of cookies that Priti still has at the end of third period is 2C/5.
<h3>How to determine the
expression?</h3>
For the first period, we have:
First period = 1/4 × C
First period = C/4.
Remaining = C - C/4 = 3C/4
For the second period, we have:
Second period = 1/5 × 3C/4
Second period = 3C/20.
Remaining = 3C/4 - 3C/20 = 12C/20
For the third period, we have:
Third period = 2/3 × 12C/20
Third period = 24C/60.
Third period = 2C/5.
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Answer:
The correct answer is B
Explanation:
There they were changed into a frost giant whose name was Ymir (e'mir). "There" provides the transition from the previous sentence and refers to the place where the transformation occurred.
Can you show us more to the question
Answer: c. Individuals should have the right to choose any religion
Answer:25.12
Explanation:
1 Simplify \frac{2}{5}s
5
2
s to \frac{2s}{5}
5
2s
.
\frac{1}{2}+\frac{2s}{5}=s-\frac{3}{4}
2
1
+
5
2s
=s−
4
3
2 Multiply both sides by 55.
\frac{5}{2}+2s=5s-\frac{15}{4}
2
5
+2s=5s−
4
15
3 Subtract 2s2s from both sides.
\frac{5}{2}=5s-\frac{15}{4}-2s
2
5
=5s−
4
15
−2s
4 Simplify 5s-\frac{15}{4}-2s5s−
4
15
−2s to 3s-\frac{15}{4}3s−
4
15
.
\frac{5}{2}=3s-\frac{15}{4}
2
5
=3s−
4
15
5 Add \frac{15}{4}
4
15
to both sides.
\frac{5}{2}+\frac{15}{4}=3s
2
5
+
4
15
=3s
6 Simplify \frac{5}{2}+\frac{15}{4}
2
5
+
4
15
to \frac{25}{4}
4
25
.
\frac{25}{4}=3s
4
25
=3s
7 Divide both sides by 33.
\frac{\frac{25}{4}}{3}=s
3
4
25
=s
8 Simplify \frac{\frac{25}{4}}{3}
3
4
25
to \frac{25}{4\times 3}
4×3
25
.
\frac{25}{4\times 3}=s
4×3
25
=s
9 Simplify 4\times 34×3 to 1212.
\frac{25}{12}=s
12
25
=s
10 Switch sides.
s=\frac{25}{12}s=
12
25
Done
Decimal Form: 2.083333