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torisob [31]
4 years ago
9

My work is as simple as a lock and key

SAT
1 answer:
Allisa [31]4 years ago
3 0
If this is biology then the answer is Enzyme. It pairs with the complementary substrate to make an Enzyme-substrate complex.
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Ping's Ice Cream Palace offers a special sundae that
jekas [21]
Let us assume number of toppings = n

Total weight of sundae = s

Quantity of Ice cream = 2 kilograms.

We need to discribe the total weight of the special sundae in kilograms by an inequality.
The sundae contains ice cream and number of toppings.

So the total weight of the sundae will be greater than the total weight of ice cream and number of toppings, because there would be some weight of the packing.

Therefore,
The total weight of the sundae > total weight of ice cream + weight of toppings.
s > 2 + n.

Where, s is the total weight of the sundae and n is the weight of toppings. I hope this was helpful!. :)
7 0
3 years ago
Achievement tests are to aptitude tests as _____ is to _____.
nadya68 [22]

Answer:

intelligence and creativity

4 0
2 years ago
Which one of these would have the strongest gravitational pull?
Rzqust [24]

Answer:

a large dance star

Explanation:

because it is bigger and heavier

6 0
3 years ago
Read 2 more answers
In 1911 harriet quimby was the first america to do what
ludmilkaskok [199]

Answer:

she was the first licensed female to fly a plane in america. She was also the first female to fly across the English channel  

Explanation:

6 0
3 years ago
The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
AlladinOne [14]

Recall that √x has a domain of x ≥ 0.

So, f(x) is defined as long as

(x + 1)/(x - 1) ≥ 0

• We have equality when x = -1

• Otherwise (x + 1)/(x - 1) is positive if both x + 1 and x - 1 are positive, or both are negative:

\begin{cases}x+1>0 \implies x>-1 \\ x-1>0 \implies x>1\end{cases} \implies x > 1

\begin{cases}x+1

Then the domain of f(x) is

x > 1   or   x ≤ -1

On the other hand, g(x) is defined by two individual square root expressions with respective domains of

• x + 1 ≥ 0   ⇒   x ≥ -1

• x - 1 ≥ 0   ⇒   x ≥ 1

but note that g(1) is undefined, so we omit it from the second domain.

Then g(x) is defined so long as both x ≥ -1 *and* x > 1 are satisfied, which means its domain is

x > 1

f(x) and g(x) have different domains, so they are not the same function.

4 0
2 years ago
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