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Rom4ik [11]
3 years ago
12

Someone please help me with this!! i really need this to pass :(

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

Option :" Use distance formula to prove that the lengths of the diagonals are equal" is correct

Step-by-step explanation:

Option : Use distance formula to prove that the lengths of the diagonals are equal" is correct.

Because " By using the coordinate geometry to prove that the diagonals of the rectangle are congruent, first we have to find the lengths of the top and bottom of the rectangle and then solve it for the lengths of the diagonals by using the distance formula".

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Help me i beg u plzzzz
Ainat [17]
We can say at month 0 she was 43 inches tall.

And at month 18 she was 52 inches tall.

We can say that x is the number of months and y is her height.

Rise/run
y2-y1/x2-x1
52-43/18-0
9/18
1/2

So the slope is 1/2 (which is what you are looking for.) and if you were to write an equation it would be y=1/2x+43

Brainliest my answer if it helps you out?
5 0
3 years ago
What is the slope of the table? <br><br> What is the y-intercept of the table?
mel-nik [20]
Slope=2
Y-intercept=12



7 0
3 years ago
Easy question i will mark braineliest
Yuki888 [10]

Answer:

<h2>0.67</h2>

Step-by-step explanation:

5(y - 3.8) = 4.7(y - 4)

Distribute 5 through the parentheses

5y - 19 = 4.7(y - 4)

Distribute 4.7 through the parentheses

5y - 19 = 4.7y - 18.8

Move ' 4.7 y ' to L.H.S and change it's sign

5y - 4.7y - 19 =  - 18.8

Move constant to R.H.S and change it's sign

5y - 4.7y =  - 18.8 + 19

Collect like terms

0.3y =  - 18.8 + 19

Calculate

0.3y = 0.2

Divide both sides of the equation by 0.3

\frac{0.3y}{0.3}  =  \frac{0.2}{0.3}

Calculate

y = 0.67

Hope this helps...

Best regards!!

3 0
3 years ago
Read 2 more answers
What is 28 divided by 4?
koban [17]
The answer is seven.
8 0
3 years ago
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Simplify the radical expression.
Ber [7]

\bf \sqrt[4]{625x^{12}y^8}~~ \begin{cases} 625=&5\cdot 5\cdot 5\cdot 5\\ &5^4\\ x^{12}=&x^{3\cdot 4}\\ &(x^3)^4\\ y^8=&y^{2\cdot 4}\\ &(y^2)^4 \end{cases}\implies \pm\sqrt[4]{5^4(x^3)^4(y^2)^4}\implies \begin{array}{llll} \pm5x^3y^2\\\\ 5|x^3|y^2\\\\ |5x^3y^2| \end{array}

8 0
3 years ago
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