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Rom4ik [11]
3 years ago
12

Someone please help me with this!! i really need this to pass :(

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

Option :" Use distance formula to prove that the lengths of the diagonals are equal" is correct

Step-by-step explanation:

Option : Use distance formula to prove that the lengths of the diagonals are equal" is correct.

Because " By using the coordinate geometry to prove that the diagonals of the rectangle are congruent, first we have to find the lengths of the top and bottom of the rectangle and then solve it for the lengths of the diagonals by using the distance formula".

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Find the height of a prism with volume 720cm3 and base area 45cm2
Morgarella [4.7K]

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The height is 16 cm

Step-by-step explanation:

It's just v/b

720/45=16

The height is 16 cm

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Find the height h of the cone. Round your answer to the nearest tenth.
denis-greek [22]

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Step-by-step explanation:

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2 years ago
Find the value of x if DE is the midsegment of triangle ABC and
Varvara68 [4.7K]

Answer

Find out the value of x.

To prove

Definition of mid- segment

It is a segment connecting the midpoints of two sides of a triangle.

It is always parallel to the third side, and the length of the midsegment is half the length of the third side.

As shown in the triangle given below.

As given

DE = 5x and BC = 11x – 15

Thus

DE = \frac{BC}{2}

5x = \frac{11x-15}{2}

5x\times 2 = 11x-15

10x = 11x-15

15 = 11x - 10x

15 = x

Therefore the value of x is 15 .

                   

8 0
3 years ago
if a coin is tossed 4 times, the odds of it coming up either heads every time or tails every time are 1:7.What is the probabilit
ivanzaharov [21]

Answer:

1

Explanation:

From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses

What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin

For four throws, it means all four are heads or all four are tails

If all four are heads, we have the probability of this happening as:

\text{ (}\frac{1}{8})^{}

if all four are tails, we have the probability as:

\frac{7}{8}

Now, the probability of either heads or all tails after 4 tosses will be:

\text{ }\frac{1}{8}\text{ + }\frac{7}{8}\text{ = 1}

8 0
1 year ago
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